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agasfer [191]
3 years ago
11

4n-6 in as a undistributed expression

Mathematics
1 answer:
lord [1]3 years ago
3 0

Answer:

2( 2n-3)

Step-by-step explanation:

4n-6

2*2 n - 2*3

Factor out the greatest common factor

2( 2n-3)

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Factor 26r3s + 52r5 – 39r2s4.
algol [13]

Answer:

13r²(2rs + 4r³ - 3s⁴)

Step-by-step explanation:

In equation 26r³s + 52r⁵ - 39r²s⁴;

The GCF of 26, 52, and 39 = 13

The GCF of r³, r⁵ and r² = r²

The GCF of s, (no "s"), and s⁴ = no "s" (Since one of the number doesn't have "s")

Now we can factor out 13r² from all three expressions;

26r³s + 52r⁵ - 39r²s⁴

=> <em>13r²(2rs) + 13r²(4r³) - 13r²(3s⁴)</em>

To factor it all together;

<u>13r²(2rs + 4r³ - 3s⁴)</u>

Hope this helps!

7 0
3 years ago
Solve the triangle.
vova2212 [387]

9514 1404 393

Answer:

  b = 71 m

  A = 83°

  C = 29°

Step-by-step explanation:

Many calculators can solve triangles. Apps are available for phone and tablet, or on the internet, like the one used here. In general, it takes less time to use one of these than to type your question into Brainly.

Given two sides and the angle between them, the Law of Cosines is the appropriate relation to use for finding the third side.

  b = √(a² +c² -2ac·cos(B))

  b = √(76² +37² -2·76·37·cos(67.75°)) ≈ √5015.48

  b ≈ 70.82005 ≈ 71 . . . meters

__

One a side and its opposite angle are known, the remaining angles are found using the Law of Sines.

  sin(A)/a = sin(B)/b

  A = arcsin(a·sin(B)/b) = arcsin(76·sin(67.75°)/70.82005) ≈ 83.33°

  A ≈ 83°

  C = arcsin(37·sin(67.75°)/70.82005) ≈ 28.92°

  C ≈ 29°

Or, you can find the remaining angle from 180° -68° -83°  = 29°.

3 0
3 years ago
The texture in this Klimt painting is? 100 points
makvit [3.9K]

Answer:

After the peak of Klimt’s Golden Phase in 1907-8, there was a decline in his use of gold leaf in his paintings, the relationship with his young protégé Egon Schiele developed, and he had separated from the Vienna Secession over its exclusion of crafts from its exhibitions.

Klimt still used precious metal leaf, including gold and platinum, in his Hope II (1907-08), originally titled Vision by the artist. As with his Hope I, it is a portrait of a woman who is heavily pregnant. The woman’s head is bowed and her eyes closed, which is echoed in the heads of three other women at the foot.

7 0
3 years ago
Read 2 more answers
Elimination process <br><br> 7a-3b = 26<br> a + 2b =11
VMariaS [17]

Answer:(a=5,b=3)

7a-3b = 26--------(1)

a + 2b =11---------(2)

on mutlplying by7 in eq 2

= 7a+14b=77-------(3)

from eq(1) and (3) (on substracting)

7a+14b=77

7a-3b=26

________

=-17b=51

b=51/17

b=3

on putting value of b in eq 1

7a-3b = 26

=7a-9=26

7a=35

a=5

Step-by-step explanation:

hope it helps

mark me brainliest

5 0
3 years ago
A group of 570 students were surveyed about the courses they were taking at their college with the following results:
garri49 [273]

Answer:

The number of students who took English and History, but not Math is 143.

Step-by-step explanation:

Denote the subject choices as follows:

<em>M</em> = a students was taking Math

<em>E</em> = a students was taking English

<em>H</em> = a students was taking History

The data provided is as follows:

N (M) = 257

N (E) = 282

N (H) = 323

n (M ∩ E) = 154

n (M ∩ H) = 171

n (E ∩ H) = 143

n (M ∩ E ∩ H) = 80

Consider the Venn diagram below.

From the provided data and the Venn diagram the value of the set E and H minus M is 143.

Thus, the number of students who took English and History, but not Math is 143.

7 0
3 years ago
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