Question

What’s the equation of a line that passes through (-6,5) (-3,-3)

Answer 1

Answer:

y=-8/3x-11

Step-by-step explanation:

SLOPE FORMULA:

$\Rightarrow \displaystyle \mathsf{\frac{Y_2-Y_1}{X_2-X_1} }}$

Y2=(-3)

Y1=5

X2=(-3)

X1=(-6)

Solve.

$\displaystyle \mathsf{\frac{-3-5}{-3-\left(-6\right)}=\frac{8}{3}=-\frac{8}{3} }}}$

Then, compute by the y-intercept.

SLOPE INTERCEPT FORM FORMULA:

$\displaystyle \mathsf{Y=MX+B}}$

y=(-8/3)x+b

(-6,5)

X=(-6)

Y=5

5=(-8/3)(-6)+b

Isolate b on one side of the equation.

(-8/3)(-6)+b=5 (Switch sides.)

Remove parenthesis.

8/3*6+b=5

8*6/3

Multiply.

8*6=48

Divide.

48/3=16

16+b=5

b+16=5 (Switch sides.)

Then, subtract 16 from both sides.

b+16-16=5-16

Solve.

5-16=-11

b=-11

So, the correct answer is y=-8/3x-11.