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Sphinxa [80]
3 years ago
15

Not sure if any of this is correct, but it’s what I got so far

Mathematics
1 answer:
Irina18 [472]3 years ago
5 0

Problem 1 is correct. You use the pythagorean theorem to find the hypotenuse.

==================================================

Problem 2 has the correct answer, but one part of the steps is a bit strange. I agree with the 132 ft/sec portion; however, I'm not sure why you wrote \frac{1 \text{ sec}}{132 \text{ ft}}=\frac{0.59\overline{09}}{78 \text{ ft}}*127 \text{ ft}

I would write it as \frac{1\text{ sec}}{132 \text{ ft}}*127 \text{ ft} = \frac{127}{132} \text{ sec} \approx 0.96 \text{ sec}

==================================================

For problem 3, we first need to convert the runner's speed from mph to feet per second.

17.5 \text{ mph} = \frac{17.5 \text{ mi}}{1 \text{ hr}}*\frac{1 \text{ hr}}{60 \text{ min}}*\frac{1 \text{ min}}{60 \text{ sec}}*\frac{5280 \text{ ft}}{1 \text{ mi}} \approx 25.667 \text{ ft per sec}

Since the runner needs to travel 90-12 = 78 ft, this means\text{time} = \frac{\text{distance}}{\text{speed}} \approx \frac{78 \text{ ft}}{25.667 \text{ ft per sec}} \approx 3.039 \text{ sec}

So the runner needs about 3.039 seconds. In problem 2, you calculated that it takes about 0.96 seconds for the ball to go from home to second base. The runner will not beat the throw. The ball gets where it needs to go well before the runner arrives there too.

-------------

The question is now: how much of a lead does the runner need in order to beat the throw?

Well the runner needs to get to second base in under 0.96 seconds.

Let's calculate the distance based on that, and based on the speed we calculated earlier above.

\text{distance} = \text{rate}*\text{time} \approx (25.667 \text{ ft per sec})*(0.96 \text{ sec}) \approx 24.64032 \text{ ft}

This is the distance the runner can travel if the runner only has 0.96 seconds. So the lead needed is 90-24.64032 = 65.35968 feet

This is probably not reasonable considering it's well over halfway (because 65.35968/90 = 0.726 = 72.6%). If the runner is leading over halfway, then the runner is probably already in the running motion and not being stationary.

As you can see, the runner is very unlikely to steal second base. Though of course such events do happen in real life. What may explain this is the reaction time of the catcher may add on just enough time for the runner to steal second base. For this problem however, we aren't considering the reaction time. Also, not all catchers can throw the ball at 90 mph which is quite fast. According to quick research, the MLB says the average catcher speed is about 81.8 mph. This slower throwing speed may account for why stealing second base isn't literally impossible, although it's still fairly difficult.

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Please help me! I will give brainly!
Fynjy0 [20]

It can be up to 20 feet taller so add 20

To the width:

88 2/3 + 20 = 108 2/3

Divide total height by the height of one story:

108 2/3 / 15 = 7.24

The building can have 7 stories.

b. 7 x 15 = 105 total feet

108 2/3 -105 = 3 2/3 feet below the restrictions

4 0
3 years ago
Read 2 more answers
A race car is driven around a circular track at a constant speed of 180mph. If the diameter is 1/2 mile, what is the angular spe
Bogdan [553]
If the diameter is 1/2 mile, that is 0.5 mile, then the radius is 0.25 -half of it!

the angular speed is theta/time, which means

 w=theta/time

but another formula for it is Velocity*radians

w=velocity*radians

velocity is 180 mph and radians are (revolution/2\pi radius), that is:

w=180*(1/2\pi*0.25)
and if we calculate this, we have: w=114.59, which is the correct answer!
4 0
3 years ago
Someone pls help asap this is due tmrw !!<br><br> x - 3y = -12<br> 2x + 3y = 3
hram777 [196]

Answer:

Step-by-step explanation:

to solve this system of equations we will add them

x-3y=-12

2x+3y=3 now +3y-3y=0

3x=-12+3

3x=-9

x=-3

plug in the first equation

-3-3y=-12

-3y=-12+3

-3y=-9

y=3

4 0
3 years ago
The sum of 5 consecutive numbers is -5. What is the largest out of the numbers?
xxTIMURxx [149]
We can say that x is the largest number.

So the sum is x + (x - 1) + (x - 2) + (x - 3) + (x - 4) = -5

Now solve for x:

x + x + x + x + x - 1 - 2 - 3 - 4 = -5

5x - 10 = -5

5x = 5

x = 1

So the largest number is 1.

Check: 1 + 0 + -1 + -2 + -3   =   -2 + -3   =   -5 so 1 is correct.
3 0
3 years ago
mr. cuddy draws a triangle with a perimeter of 36cm. Principal Aranda says that the longest side measures 18 cm, How do you know
hichkok12 [17]

Answer:

See the procedure

Step-by-step explanation:

we know that

<u>The Triangle Inequality Theorem</u>, states that the sum of the lengths of any two sides of a triangle is greater than the length of the third side

Let

a,b,c the lengths side of triangle

c is the greater side

The perimeter is equal to

P=a+b+c

P=36 cm

If c=18 cm

then

a+b=18

Applying the Triangle Inequality Theorem

a+b > c

18 > 18  ----> is not true

therefore

Principal Aranda is incorrect

The larger side cannot measure 18 cm

The largest side must be less than 18 cm

3 0
3 years ago
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