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Paha777 [63]
3 years ago
5

PLEASE HELP. In the figures △CDA ≅ △XYZ

Mathematics
2 answers:
Dafna11 [192]3 years ago
8 0

Answer:

Option C is correct.

Step-by-step explanation:

Given: ΔCDA \cong ΔXYZ

Congruent triangles states that when they have  exactly the same three sides and exactly the same three angles.

therefore,

by CPCT (Corresponding Part of  Congruent Triangle) in triangle CDA and triangle XYZ

we have;

\angle C \cong \angle X

\angle D \cong \angle Y

\angle A \cong \angle Z  


irga5000 [103]3 years ago
6 0
<span>C. ∠C ≅ ∠X
    ∠D ≅ ∠Y
   ∠A ≅ ∠Z</span>
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By definition, the determinant equals ad - bc. What is the value of when x = -2 and y = 3? I NEED HELP PLEASE
sergiy2304 [10]

Answer:

<h3>B. -84</h3>

Step-by-step explanation:

Taking the determinant of the matrices we will have;

= 4x(5y) - 2x(3y)

= 20xy - 6xy

= 14xy

Given x = -2 and y = 3

Determinant = 14(-2)(3)

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4 0
2 years ago
A boy makes a cuboid of plasticine of sides 5cm, 2cm, 5cm. How manny such cuboids will he need to form a cube?
ruslelena [56]

Answer:

Step-by-step explanation:

L.C.M. of 5,2=10

so it should be  of dimensions 10×10×10

it should have 5 cuboids in first row.

then it will make a cuboid 5×10×5

5 cuboids in the second row on top of first row .

Then it will make 5×10×10 cuboid

To make 10×10×10

double the cuboids  to make the length=10 and height=10..

so in all 20 cuboids are needed.

2 rows of 5 cuboids on the floor and 2 rows of 5 cuboids on the top.

in all 10 cuboids of  dimensions 5×2×5

so 9 more cuboids are needed to make a c

3 0
3 years ago
What is the third quartile, Q3, of the following distribution?
GREYUIT [131]

Answer:

The third quartile is:

Q_3=29

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile Q_3

For a set of n data organized in the form:

x_1, x_2, x_3, ..., x_n

The third quartile is  Q_3:

Q_3=x_{\frac{3}{4}(n+1)}

With n=20

Q_3=x_{\frac{3}{4}(20+1)}

Q_3=x_{15.75}

The third quartile is between x_{15}=29 and x_{16}=29

Then

Q_3 =x_{15} + 0.75*(x_{16}- x_{15})

Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29

5 0
3 years ago
Read 2 more answers
Nathan is organizing textbooks on his bookshelf. He has a Spanish textbook, a math
Ghella [55]

Answer:

6 ways

Step-by-step explanation:

Given:

Books: Spanish, Maths and History textbooks (1 each)

Required

Determine the number of arrangements

In total, Nathan has 3 books.

The number of arrangements (n) is as follows:

The first book can be lined in 3 ways

The second book can be lined in 2 ways

The third book can be lined in 1 way

So,

n = 3 * 2 * 1

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3 0
2 years ago
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A college surveys 300 graduates and finds 98 graduated with honors and 207 had one or both parents graduate from college. Of the
musickatia [10]

Answer:

20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Graduated with honors:

98 students graduated with honors. Of those, 79 had at least one parent graduating from college. So 98 - 79 = 19 did not.

Of 300 students, 207 had one or both parents graduate from college. So 300 - 207 = 93 did not have at least one parent graduating.

Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Of the 93 with no graduated parent, 19 earned honors

19/93 = 0.2043

20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

4 0
3 years ago
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