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3 years ago

PLEASE HELP. In the figures △CDA ≅ △XYZ

Mathematics

2 answers:

Dafna11 [192]3 years ago

8 0

Answer:

Option C is correct.

Step-by-step explanation:

Given: ΔCDA $\cong$ ΔXYZ

Congruent triangles states that when they have exactly the same three sides and exactly the same three angles.

therefore,

by CPCT (Corresponding Part of Congruent Triangle) in triangle CDA and triangle XYZ

we have;

$\angle C \cong \angle X$

$\angle D \cong \angle Y$

$\angle A \cong \angle Z$

irga5000 [103]3 years ago

6 0

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sergiy2304 [10]

Answer:

Step-by-step explanation:

Taking the determinant of the matrices we will have;

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2 years ago

A boy makes a cuboid of plasticine of sides 5cm, 2cm, 5cm. How manny such cuboids will he need to form a cube?

ruslelena [56]

Answer:

Step-by-step explanation:

L.C.M. of 5,2=10

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3 years ago

What is the third quartile, Q3, of the following distribution?

GREYUIT [131]

Answer:

The third quartile is:

$Q_3=29$

Step-by-step explanation:

First organize the data from lowest to highest

4, 5, 10, 12, 14, 16, 18, 20, 21, 21, 22, 22, 24, 26, 29, 29, 33, 34, 43, 44

Notice that we have a quantity of n = 20 data

Use the following formula to calculate the third quartile $Q_3$

For a set of n data organized in the form:

$x_1, x_2, x_3, ..., x_n$

The third quartile is $Q_3$ :

$Q_3=x_{\frac{3}{4}(n+1)}$

With n=20

$Q_3=x_{\frac{3}{4}(20+1)}$

$Q_3=x_{15.75}$

The third quartile is between $x_{15}=29$ and $x_{16}=29$

Then

$Q_3 =x_{15} + 0.75*(x_{16}- x_{15})$

$Q_3 =29 + 0.75*(29- 29)\\\\Q_3 =29$

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3 years ago

Read 2 more answers

Nathan is organizing textbooks on his bookshelf. He has a Spanish textbook, a math

Ghella [55]

Answer:

6 ways

Step-by-step explanation:

Given:

Books: Spanish, Maths and History textbooks (1 each)

Required

Determine the number of arrangements

In total, Nathan has 3 books.

The number of arrangements (n) is as follows:

The first book can be lined in 3 ways

The second book can be lined in 2 ways

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So,

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2 years ago

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A college surveys 300 graduates and finds 98 graduated with honors and 207 had one or both parents graduate from college. Of the

musickatia [10]

Answer:

20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Graduated with honors:

98 students graduated with honors. Of those, 79 had at least one parent graduating from college. So 98 - 79 = 19 did not.

Of 300 students, 207 had one or both parents graduate from college. So 300 - 207 = 93 did not have at least one parent graduating.

Find the probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

Of the 93 with no graduated parent, 19 earned honors

19/93 = 0.2043

20.43% probability that a randomly chosen graduate from these 300 graduated with honors given that neither parent graduated from college.

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3 years ago