Answer:
Step-by-step explanation:
We are looking for what number times .50 makes the equation true.
So, just do backwards equation:
Thus, meaning that what multiplied by 0.50 is equal to 17?
[tex]0.50 * 34[tex]
[tex]==> 17[tex]
X = (2^2)^(2.5)
<span>x = 2^(2 * 2.5) </span>
<span>x = 2^5 </span>
<span>x = 32
</span>y^(-3/2) = 125
<span>y^(-3) = 125^2 </span>
<span>y^(-3) = (5^3)^2 </span>
<span>y^(-3) = (5^2)^3 </span>
<span>y^(-3) = 25^3 </span>
<span>y = 25^(-1) </span>
<span>y = 1/25 </span>
<span>x/y => </span>
<span>32 / (1/25) => </span>
<span>32 * 25 => </span>
<span>800 is the simplest form of above
</span>
Answer:
a) 25 is 3 standard deviation from the mean
b) Is far away from the mean, only 0,3 % away from the right tail
c) 25 is pretty close to the mean (just a little farther from 1 standard deviation)
Step-by-step explanation:
We have a Normal Distribution with mean 16 in.
Case a) we also have a standard deviation of 3 inches
3* 3 = 9
16 (the mean) plus 3*σ equal 25 in. the evaluated value, then the value is 3 standard deviation from the mean
Case b) 25 is in the range of 99,7 % of all value, we can say that value is far away from the mean, considering that is only 0,3 % away from the right tail
Case c) If the standard deviation is 7 then
mean + 1*σ = 16 + 7 =23
25> 23
25 is pretty close to the mean only something more than 1 standard deviation
Answer:
AB = 9/2 cm
AB = 4.5 cm
Step-by-step explanation:
The area of small rectangle
x * (x-4) = x^2 -4x
The area of the big rectangle
The height is 2x +x and the width is x-2
(2x+x) * (x-2)
(3x) * (x-2)
3x^2 -6x
Add the areas together
x^2 -4x + 3x^2 -6x
4x^2 -10x
This is equal to 36
4x^2 -10x=36
Subtract 36 from each side
4x^2 -10x -36=36-36
4x^2 -10x-36=0
Divide each side by 2
2x^2 -5x -18=0
Factor
(x + 2) (2 x - 9) = 0
Using the zero product property
x+2=0 2x-9=0
x = -2 2x =9
x = -2 x = 9/2
Since we cant have a negative length
x = 9/2
AB = 9/2 cm
Answer:
946 sq inches
Step-by-step explanation:
28*7=196
30*25=750
750+196=946 i think thats how you do it lol
(=^w^=)
