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poizon [28]
3 years ago
11

Please help me with this, ASAP. Please and thank you! D:

Mathematics
1 answer:
creativ13 [48]3 years ago
8 0
Please help me with math if you can
If your able to of course
Help mr///////)()&&)&!!,;$?&&,;)$,५$,(७,
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How would you solve this problem step by step ?<br><br> 4√15(2√2 + √5)
xxTIMURxx [149]

~~4\sqrt{15} \left( 2\sqrt 2 + \sqrt 5 \right)\\\\=8\sqrt{15} \sqrt 2 + 4\sqrt{15} \sqrt 5\\\\=8\sqrt{15\times 2}+4 \sqrt{15 \times 5}\\\\=8\sqrt{30}+4\sqrt{3 \times 5 \times 5}\\\\=8\sqrt{30}  + 4 \sqrt{3\times 5^2}\\\\=8\sqrt{30} + 4\cdot 5 \sqrt 3\\\\=8\sqrt{30} +20\sqrt{3}

4 0
2 years ago
Share 747 pound in the ratio 2:7 betwen tom and ben
Yuliya22 [10]
2p + 7p = 747
9p = 747 divded by 9 = 83
2 * 83 = 166    7 * 83 = 581

Hope it helps
7 0
3 years ago
Select the correct answer.
Alekssandra [29.7K]
Please rewrite the question or add a picture for it
3 0
3 years ago
Find (f - g)(x) if f(x) = x2 ­- x - 6 and g(x) = 2x2 - 3x + 4
Nadya [2.5K]
For this question we just have to re-substitute the expressions for their respective functions by assigning them in a plausible condition for two functions. Here, the first function of "x" is subtracted by a second function of "x". The expressions are assigned according to the first and second function expressions in each case or condition.

All we have to do is distribute the parentheses for second expression to deploy positive addition between 2x^2 and 3x. Furthermore grouping all the like terms to get the required answer to this query. So, let me express this via LaTeX interpreter equation editor for a better understanding and clear all the doubts for these forms of queries.

\mathbf{Since, \: \: f(x) = x^2 - x - 6}

\mathbf{\therefore \quad \Big(x^2 - x - 6 - g(x) \Big) \: (x)}

\mathbf{Since, \: \: g(x) = 2x^2 - 3x + 4}

\mathbf{\therefore \quad x^2 - x - 6 - (2x^2 - 3x + 4)}

\mathbf{x^2 - x - 6 - (2x^2) - (- 3x) - (+ 4)}

\mathbf{x^2 - x - 6 - 2x^2 + 3x - 4}

\mathbf{x^2 - 2x^2 - x + 3x - 6 - 4}

\mathbf{x^2 - 2x^2 + 2x - 6 - 4}

\mathbf{- x^2 + 2x - 6 - 4}

\boxed{\mathbf{\underline{Required \: \: Answer: \: - x^2 + 2x - 10}}}

Hope it helps.
6 0
3 years ago
A) C = √19-8√3<br> b) D = √5-2√6<br> c) √(√2+1)^2 - √(√2-5)^2<br> d) E = √(√7+√13) - √(7-13)
lord [1]
D be a explanation

Explain
7 0
3 years ago
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