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sergij07 [2.7K]
3 years ago
14

What is the place value for 3 in 6,035

Mathematics
1 answer:
bonufazy [111]3 years ago
5 0
The place value in 6,035 is 30
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Round up 395,621 to the nearest ten thousand
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396,000
because 5 goes up and anything lower than five stays the same
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3 years ago
The velocity v that an object r units
erastova [34]

Answer:

M=v^2r / 2G

Step-by-step explanation:

Open the file, it is solved for you, your welcome.

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3 years ago
Find the average value of f over region
yan [13]
The area of D is given by:

\int\limits \int\limits {1} \, dA = \int\limits_0^7 \int\limits_0^{x^2} {1} \, dydx  \\  \\ = \int\limits^7_0 {x^2} \, dx =\left. \frac{x^3}{3} \right|_0^7= \frac{343}{3}

The average value of f over D is given by:

\frac{1}{ \frac{343}{3} }  \int\limits^7_0  \int\limits^{x^2}_0 {4x\sin(y)} \, dydx  = -\frac{3}{343}  \int\limits^7_0 {4x\cos(x^2)} \, dx  \\  \\ =-\frac{3}{343} \int\limits^{49}_0 {2\cos(t)} \, dt=-\frac{6}{343} \left[\sin(t)\right]_0^{49} \, dt=-\frac{6}{343}\sin49
3 0
3 years ago
If the diagonals of a parallelogram are equal, then show that it is a rectangle.
Harlamova29_29 [7]

Answer:

Given: In parallelogram ABCD, AC=BD

To prove : Parallelogram ABCD  is rectangle.

Proof : in △ACB and △BDA

AC=BD  ∣ Given

AB=BA ∣ Common

BC=AD ∣ Opposite sides of the parallelogram ABCD

△ACB ≅△BDA∣SSS Rule

∴∠ABC=∠BAD...(1) CPCT

Again AD ∥ ∣ Opposite sides of parallelogram ABCD

AD ∥BC and the traversal AB intersects them.

∴∠BAD+∠ABC=180∘ ...(2) _ Sum of consecutive interior angles on the same side of the transversal is 

180∘

From (1) and (2) ,

∠BAD=∠ABC=90∘

∴∠A=90∘ and ∠C=90∘

Parallelogram ABCD is a rectangle.

4 0
2 years ago
Work out the reciprocal of 0.4
Bond [772]

Answer:

1/0.4=10/4=5/2...............

4 0
2 years ago
Read 2 more answers
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