2-3*(z-5)+11=4 what is the value of z

Mathematics

1 answer:

wel3 years ago

6 0

2-3(z-5)+11=4

Distribute

2-3z+15+11=4

Move the constants to gether but make sure they keep thei signs

2+15+11-3z=4

Simplify

28-3z=4

Start to Isolate the variable by subtracting 28 from both sides of the equation

-3z=-24

Completely isolate the variable by deviding the whole equation by -3

z=8

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What is 0.85 as fraction? Show your work please and thank you!

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Answer:

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Step-by-step explanation:

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3 years ago

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Find a formula for the described function. A rectangle has perimeter 16 m. Express the area A of the rectangle as a function of

Alex17521 [72]

Part A:

Let the length of one of the sides of the rectangle be L, then the length of the other side is obtained as follow.

Let the length of the other side be x, then

$2(L+x)=16 \\ \\ \Rightarrow L+x=8 \\ \\ \Rightarrow x=8-L$

Thus, if the length of one of the side is x, the length of the other side is 8 - L.

Hence, the area of the rectangle in terms of L is given by

$L(8 - L) = 8L-L^2$

Part B:

To find the domain of A

Recall that the domain of a function is the set of values which can be assumed by the independent variable. In this case, the domain is the set of values that L can take.

Notice that the length of a side of a rectangle cannot be negative or 0, thus L cannot be 8 as 8 - 8 = 0 or any number greater than 8.

Hence the domain of the area are the set of values between 0 and 8 not inclusive.

Therefore,

$dom(Area)=0\ \textless \ L\ \textless \ 8 \ or \ (0, 8)$