Any help please I gladly appreciate it!!!

24=3(n-5) solve for n

mario62 [17]

Answer:

n = 13

Step-by-step explanation:

24 = 3 (n-5)

3n - 15 = 24

3n = 24 +15

3n = 39

n = 39/3

n = 13

6 0

3 years ago

Read 2 more answers

I need to solve for x using the pythagorean theorem some how (I think) please only answer if you can give a hint or the answer w

borishaifa [10]

$\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b \qquad \begin{cases} c=\stackrel{hypotenuse}{\stackrel{3959+5.9}{3964.9}}\\ a=\stackrel{adjacent}{3959}\\ b=\stackrel{opposite}{x}\\ \end{cases} \\\\\\ \sqrt{3964.9^2-3959^2}=x\implies \sqrt{46751.01}=x\implies 216.22\approx x$

4 0

3 years ago

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Suppose we have two thermometers. One thermometer is very precise but is delicate and heavy (X). We have another thermometer tha

Temka [501]

Answer:

a)H0: β1= 1 and Ha: β1 ≠1

b) The test statistic is____.t= b- β/ sb

c) The p-value is____.0.999144

(d) Therefore, we can conclude that:_____. there is not enough evidence to reject the null hypothesis.

2) The data provides no evidence at the 0.1 significance level that these thermometers are not consistent.

Step-by-step explanation:

The null and alternate hypotheses are

H0: β1= 1 and Ha: β1 ≠1

The significance level is alpha= 0.1 but ∝/2 =0.1/2= 0.05 for two tailed test.

The critical region at t ∝/2 (29)= t ≤ - 1.699 , t ≥ 1.699

The test statistic is

t= b- β/ sb

which has t distribution with υ= 31-2= 29 degrees of freedom.

Calculations

Ŷ = a +bX

b = SPxy /SS x= Σ(xi-x`)(yi-y`)/Σ(xi-x`)²

b = 39671.6/39680= 0.9998

a = y` - bx`

x`= 60

y`= 59.989

a = 59.989 -0.9998*60 = 0.001734

Syx²= Σ( yi -y`)²/ n-2= 39663.3857/ 29=1367.68965

Syx= 36.9822

Sb= Syx/ √∑ (x-x`)²

Sb= 36.9823/ √39680

Sb= 36.9823/ 199.984

Sb= 0.18493

x-x` y-y` (x-x`)² (x-x`)(y-y`)

-60 -59.969 3600 3598.1419

-56 -55.999 3136 3135.9458

-52 -52.079 2704 2708.1097

-48 -47.959 2304 2302.0335

-44 -43.899 1936 1931.5574

-40 -39.989 1600 1599.5613

-36 -36.009 1296 1296.3252

-32 -31.899 1024 1020.769

-28 -28.049 784 785.3729

-24 -23.959 576 575.0168

-20 -19.989 400 399.7806

-16 -15.939 256 255.0245

-12 -12.039 144 144.4684

-8 -7.989 64 63.9123

-4 -4.119 16 16.4761

0 -0.08903 0 0

4 3.921 16 15.6839

8 7.961 64 63.6877

12 12.121 144 145.4516

16 16.031 256 256.4955

20 20.021 400 400.4194

24 24.111 576 578.6632

28 28.071 784 785.9871

32 31.751 1024 1016.031

36 36.031 1296 1297.1148

40 39.961 1600 1598.4387

44 43.881 1936 1930.7626

48 48.021 2304 2305.0065

52 52.001 2704 2704.0503

56 56.051 3136 3138.8542

Putting the values

The test statistic is

t= b- β/ sb

t= 0.9998-1/ 0.18493 ( β=1 given)

t=-0.0010815

Since the calculated t=-0.0010815 does not lie in the critical region t ∝/2 (29)= t ≤ - 1.699 , t ≥ 1.699 we conclude that these thermometers seem to be measure temperatures.

The p-value is ≈ 0.999144

there is not enough evidence to reject the null hypothesis.

7 0

3 years ago

The accounting department analyzes the variance of the weekly unit costs reported by two production departments. A sample of cos

madreJ [45]

Answer:

$F=\frac{s^2_2}{s^2_1}=\frac{5.4}{2.3}=2.348$

$p_v =2*P(F_{15,15}>2.348)=0.109$

And we can use the following excel code to find the p value:"=2*(1-F.DIST(2.348,15,15,TRUE))"

Since the $p_v > \alpha$ we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the variation is different between the two groups at 10% of significance.

Step-by-step explanation:

Assuming the following question :"The accounting department analyzes the variance of the weekly unit costs reported by two production departments. Asample of 16 cost reports for each of the two departments shows cost variances of 2.3 and 5.4, respectively. Is this sample sufficient to conclude that the two production departments differ in terms of unit cost variance? Use α= .10."

Data given and notation

$n_1 = 16$ represent the sampe size for sample 1

$n_2 =16$ represent the sample size for sample 2

$s^2_1 = 2.3$ represent the sample variance for sample 1

$s^2_2 = 5.4$ represent the sample variance for sample 2

$\alpha=0.1$ represent the significance level provided

Confidence =0.9 or 9%

F test is a statistical test that uses a F Statistic to compare two population variances, with the sample deviations s1 and s2. The F statistic is always positive number since the variance it's always higher than 0. The statistic is given by:

$F=\frac{s^2_2}{s^2_1}$

Solution to the problem

System of hypothesis

We want to test if the variation is equal for both groups or no, so the system of hypothesis are:

H0: $\sigma^2_1 = \sigma^2_2$

H1: $\sigma^2_1 \neq \sigma^2_2$

Calculate the statistic

Now we can calculate the statistic like this:

$F=\frac{s^2_2}{s^2_1}=\frac{5.4}{2.3}=2.348$

Now we can calculate the p value but first we need to calculate the degrees of freedom for the statistic. For the numerator we have $n_2 -1 =16-1=15$ and for the denominator we have $n_1 -1 =16-1=15$ and the F statistic have 15 degrees of freedom for the numerator and 15 for the denominator. And the P value is given by:

P value

Since is a bilateral test the p value is given by

$p_v =2*P(F_{15,15}>2.348)=0.109$

And we can use the following excel code to find the p value:"=2*(1-F.DIST(2.348,15,15,TRUE))"

Conclusion

Since the $p_v > \alpha$ we have enough evidence to FAIL to reject the null hypothesis. And we can say that we don't have enough evidence to conclude that the variation is different between the two groups at 10% of significance.

4 0

4 years ago

The definition of power

kicyunya [14]

Answer:

When you look in the dictinary it says this...*pick any they all will get the answer correct!

Step-by-step explanation:

definition for power in math!

In mathematics, power refers to the number arrived at by raising a number to an exponent.

brainliest? hope this helps!

8 0

3 years ago