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Ostrovityanka [42]
2 years ago
10

Which of the following graphs represent a function? Graph A Graph B Graph Graphc Graph A and Graph C.​

Mathematics
1 answer:
Anuta_ua [19.1K]2 years ago
3 0

Answer: A and C

Step-by-step explanation:

Each input value gives only one output value.

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Answer:

2nd and the last one

Step-by-step explanation:

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2.50

Step-by-step explanation:

that is just barely less then a 90° so I rounded it up to a 90° and the closest answer is 2.50

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MYP 1 Mathematics Summative Assessment Unit 4 Example
zhuklara [117]

You just have to answer to all of the questions and bullet points. Think about them, and do some sketches. In the end that will help you to end the assignment.

Hope it helped.

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3 years ago
Given that (5,-8) is on the graph of f(x), find
My name is Ann [436]

Answer:

The corresponding point for the function  f(x + 2) is (3 , -8)

Step-by-step explanation:

* Lets talk about the transformation

- If the function f(x) translated horizontally to the right  by h units,

 then the new function g(x) = f(x - h)

- If the function f(x) translated horizontally to the left  by h units,

 then the new function g(x) = f(x + h)

* Lets solve the problem

- There is a graph of f(x)

- Point (5 , -8) lies on the graph of f(x)

- The graph of f(x) change to f(x + 2)

∵ f(x) ⇒ f(x + 2)

∵ If the function f(x) translated horizontally to the left  by h units,

  then the new function g(x) = f(x + h)

∴ f(x) translated horizontally 2 units to the left

∴ Any point on the graph its x-coordinate translated 2 units

  to the left

∴ The x-coordinate of any point on the graph is subtracted by 2

∵ Point (5 , -8) lies on the graph

∴ Its corresponding point is (5 - 2 , -8) = (3 , -8)

* The corresponding point for the function  f(x + 2) is (3 , -8)

7 0
3 years ago
Show that y=cos(t)y=cos(t) is a solution to (dydt)2=1−y2(dydt)2=1−y2. Enter your answers below in terms of the independent varia
GrogVix [38]

Answer:

(\frac{dy}{dt})^2=sin^2t

Step-by-step explanation:

y=cost

DE :(\frac{dy}{dt})^2=1-y^2

If y is a solution of given DE then it satisfied the DE.

Differentiate w.r.t t

\frac{dy}{dt}=-sint

Using the formula

\frac{d(cosx)}{dx}=-sinx

LHS:(\frac{dy}{dt})^2=(-sint)^2=sin^2t

RHS

1-y^2=1-cos^2t=sin^2t

By using the formula

sin^2t=1-cos^2t

LHS=RHs

Hence, y is a solution of given DE

(\frac{dy}{dt})^2=sin^2t

7 0
3 years ago
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