Answer:
yes
Step-by-step explanation:
City hall to post office = 6 1/2 miles = represented by f
city hall to library site = 1 1/4 miles = represented by d
library site to post office = unknown. = represented by e
City hall to library site PLUS library site to post office IS EQUAL to city hall to post office
d + e = f
1 1/4 + e = 6 1/2
find e.
e = 6 1/2 - 1 1/4
e = 13/2 - 5/4
e = (13*2)/(2*2) - 5/4
e= 26/4 - 5/4
e = (26-5)/4
e = 21/4
e = 5 1/4 distance from library site to post office.
To check:
d + e = f
1 1/4 + e = 6 1/2
1 1/4 + 5 1/4 = 6 1/2
6 2/4 = 6 1/2
6 1/2 = 6 1/2
Answer:
12.8 seconds
Step-by-step explanation:
13.8-1=12.8.... unless I'm wrong?
Answer:
<em>LCM</em> = 
Step-by-step explanation:
Making factors of 
Taking
common:

Using <em>factorization</em> method:

Now, Making factors of 
Taking
common:

Using <em>factorization</em> method:

The underlined parts show the Highest Common Factor(HCF).
i.e. <em>HCF</em> is
.
We know the relation between <em>LCM, HCF</em> of the two numbers <em>'p' , 'q'</em> and the <em>numbers</em> themselves as:

Using equations <em>(1)</em> and <em>(2)</em>:

Hence, <em>LCM</em> = 
9. D because it fits the description when it is graphed.
11. D because it has the correct vertex, which is (1.5, 4.75).
12. f(x)=-4(x-2)²+16 works with the table and provided graph!
13. 0 isn't a zero for f(x), so B is correct (the zeros are 1/2 and 4).
14. The width is about 3.831.
15. The answer is B because the equation for a parabola in this form is:
f(x) = (x - r₁)(x - r₂)
Every one of these except for 15 was solved using desmos, a graphing calculator.
Hope this helps!