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arlik [135]
4 years ago
15

The area of a rectangle, A = 1 x w is represented by the expression 24x^6y^15 Which could be the dimensions of the

Mathematics
2 answers:
yulyashka [42]4 years ago
6 0

Answer:

The correct answer is :l=2x^5y^8,w = 12xy^7

Step-by-step explanation:

Let the dimension of the rectangle be l and w.

A = 24x^6y^{15}

24x^6y^{15}=l\times w

A) If the dimension are :

l=2x^5y^8,w = 12xy^7

Area of the rectangle

= 2x^5y^8\times 12xy^7=24x^6y^{15}=A

B) If the dimension are :

l=6x^2y^3,w = 4x^3y^5

Area of the rectangle

= 6x^2y^3\times 4x^3y^5=24x^5y^{8}\neq A

C) If the dimension are :

l=10x^6y^{15},w = 14x^6y^{15}

Area of the rectangle

= 10x^6y^{15}\times 14x^6y^{15}=140x^{12}y^{30}\neq A

D) If the dimension are :

l=9x^4y^{11},w = 12x^2y^4

Area of the rectangle

= 9x^4y^{11}\times 12x^2y^4=108x^6y^{15}\neq A

frutty [35]4 years ago
4 0

Answer:

A. 2x^5y^8 and 12xy^7

Step-by-step explanation:

The question is on laws of indices

when we have x^a × x^b = x^(a+b)

Given in the question 24x^6y^15

24 could be 2×12............for the length and width

Then x^6 = x^1 × x^5 = x^(1+5) = x^6

And  y^15 = y^8 ×y^7 = y^(8+7) = y^(15)

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