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Kamila [148]
3 years ago
11

A triangular section of land is fenced off due to contamination. Two sides of the triangle are each 16 meters ( 16m) longer than

the third side.
If 122m of fencing is used to enclose the area, what is the length of the shortest side, in meters?
Mathematics
2 answers:
Sphinxa [80]3 years ago
8 0

Answer: the shortest side is 30m

Step-by-step explanation:

Let the shortest side be a meters

If side 2 is 16m longer than the shortest side, then it is (16+a)meters.

The same goes with side 3.

Then,

a + (16+a) + (16+a) = 122m

32 + 3a = 122m

Collecting like terms together,

3a = 122 - 32

3a = 90

Divide by coefficient of a

3a/3 = 90/3

a = 30 meters

Check:

30 + (16+30) + (16+30)

30 + 46 + 46 = 112

IgorC [24]3 years ago
7 0

Answer:

Shortest side = 30 m long.

Step-by-step explanation:

Let the shortest side be x meters long.

The other 2 sides are both  x + 16 m.

The perimeter is 122 m so

x + 2(x + 16) = 122

x + 2x + 32 = 122

3x = 122 - 32

3x =  90

x = 30 m.

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2 years ago
Dahlia is trying to decide which bank she should use for a loan she wants to take out. In either case, the principal of the loan
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Answer:

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Step-by-step explanation:

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3 0
2 years ago
If the measure of angle BCD=51 degrees, solve for x.
BabaBlast [244]

Answer:

x=5

Step-by-step explanation:

step 1

Find the measure of angle EFD

In this problem I will assume that ABCD is a parallelogram

In a parallelogram opposite angles are congruent and consecutive angles are supplementary

so

m\ angle BCD=m\angle BED=51^o

m\ angle FED=(1/2)m\angle BED=(1/2)51^o=25.5^o --- > given problem

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

In the triangle EFD

m\ angle FED+m\ angle FDE+m\ angle EFD=180^o

substitute the given values

25.5^o+55^o+m\ angle EFD=180^o

80.5^o+m\ angle EFD=180^o

m\ angle EFD=180^o-80.5^o

m\ angle EFD=99.5^o

step 2

Find the measure of angle EFB

we know that

m\angle EFB+m\angle EFD=180^o ---> by supplementary angles

we have

m\ angle EFD=99.5^o

substitute

m\angle EFB+99.5^o=180^o

m\angle EFB=180^o-99.5^o

m\angle EFB=80.5^o

step 3

Find the value of x

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so

In the triangle EBF

m\ angle BEF+m\ angle EFB+m\ angle EBF=180^o

we have

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m\angle EFB=80.5^o

m\angle EBF=(14x+4)^o

substitute

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solve for x

Combine like terms

(14x+110)^o=180^o

14x=180-110

14x=70

x=5

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