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bagirrra123 [75]
3 years ago
11

If you drive at 100km/hr for 6 hours, how far will you go

Mathematics
2 answers:
tatiyna3 years ago
6 0
600km. Because 100 kilometers an hour times 6 equals a distance of 600km.
netineya [11]3 years ago
5 0
You times the speed by the time given to you:
100*6 = 600

You would travel 600km,
Hope this helps! :)
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Answer:

exact form : 3/2

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Are the two lines parallel, perpendicular, or neither?
RideAnS [48]

Graph 1 neither

Graph 2 neither

Graph 3 perpendicular

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5 0
3 years ago
According to government data, 20% of employed women have never been married. If 10 employed women are selected at random, what i
Ierofanga [76]

Answer:

a) P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

b) P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)

P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107

P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268

P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

And replacing we got:

P(X\leq 2) = 0.107+0.268+0.302=0.678

c) For this case we want this probability:

P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302

P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268

P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107

And replacing we got:

P(X \geq 8) = 0.677

And replacing we got:

P(X\geq 8)=0.0000779

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".  

Let X the random variable of interest, on this case we now that:  

X \sim Bin (n=10 ,p=0.2)

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}  

Solution to the problem

Let X the random variable "number of women that have never been married" , on this case we now that the distribution of the random variable is:  

X \sim Binom(n=10, p=0.2)  

Part a

We want to find this probability:

P(X=2)

And using the probability mass function we got:

P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

Part b

For this case we want this probability:

P(X\leq 2) = P(X=0) + P(X=1) +P(X=2)

We can find the individual probabilities and we got:

P(X=0) = (10C0) (0.2)^0 (1-0.2)^{10-0}= 0.107

P(X=1) = (10C1) (0.2)^1 (1-0.2)^{10-1}= 0.268

P(X=2) = (10C2) (0.2)^2 (1-0.2)^{10-2}= 0.302

And replacing we got:

P(X\leq 2) = 0.107+0.268+0.302=0.678

Part c

For this case we want this probability:

P(X\geq 8) = P(X=8) + P(X=9) +P(X=10)

But for this case the probability of success is p =1-0.2= 0.8

We can find the individual probabilities and we got:

P(X=8) = (10C8) (0.8)^8 (1-0.8)^{10-8} =0.302

P(X=9) = (10C9) (0.8)^9 (1-0.8)^{10-9} =0.268

P(X=10) = (10C10) (0.8)^{10} (1-0.8)^{10-10} =0.107

And replacing we got:

P(X \geq 8) = 0.677

3 0
3 years ago
Can someone please help me with this quiz or does anyone have the answer key it’s by Gina Wilson.
tatiyna

Answer:

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Step-by-step explanation:

6 0
3 years ago
A manager at a local company asked his employees how many times they had given blood in the last year. The results of the survey
Lubov Fominskaja [6]

Answer:

Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779

And the deviation would be:

Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54

Step-by-step explanation:

For this case we have the following distribution given:

X        0         1       2       3       4         5        6

P(X)  0.3   0.25   0.2   0.12   0.07   0.04   0.02

For this case we need to find first the expected value given by:

E(X) = \sum_{i=1}^n X_i P(X_I)

And replacing we got:

E(X)= 0*0.3 +1*0.25 +2*0.2 +3*0.12 +4*0.07+ 5*0.04 +6*0.02=1.61

Now we can find the second moment given by:

E(X^2) =\sum_{i=1}^n X^2_i P(X_i)

And replacing we got:

E(X^2)= 0^2*0.3 +1^2*0.25 +2^2*0.2 +3^2*0.12 +4^2*0.07+ 5^2*0.04 +6^2*0.02=4.97

And the variance would be given by:

Var(X) = E(X^2) -[E(X)]^2 = 4.97 -(1.61)^2 =2.3779

And the deviation would be:

Sd(X) =\sqrt{2.3779}= 1.542 \approx 1.54

 

8 0
3 years ago
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