Answer:

Step-by-step explanation:





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Answer:
a^2b^5
Step-by-step explanation:
Anything divided by itself is 1.
That is, anything multiplied by its reciprocal is 1. This value (the reciprocal of the expression) is called the "multiplicative inverse." Its value is that the product of an expression and its multiplicative inverse is 1, the multiplicative identity element. (Anything times 1 is itself.)
So, to get 1 as a product, multiply by 1/(a^2b^5), which is to say, divide by a^2b^5 to get 1 as a quotient.
Answer:
x = 6
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtract Property of Equality
<u>Algebra I</u>
- Terms/Coefficients/Degrees
- Expand by FOIL (First Outside Inside Last)
- Factoring
- Multiple Roots
<u>Trigonometry</u>
[Right Triangles Only] Pythagorean Theorem: a² + b² = c²
- a is a leg
- b is another leg
- c is the hypotenuse
Step-by-step explanation:
<u>Step 1: Identify</u>
<em>a</em> = x + 3
<em>b</em> = x
<em>c</em> = √117
<u>Step 2: Solve for </u><em><u>x</u></em>
- Substitute [PT]: (x + 3)² + x² = (√117)²
- Expand [FOIL]: x² + 6x + 9 + x² = (√117)²
- Combine like terms: 2x² + 6x + 9 = (√117)²
- Exponents: 2x² + 6x + 9 = 117
- [SPE] Subtract 117 on both sides: 2x² + 6x - 108 = 0
- Factor out GCF: 2(x² + 3x - 54) = 0
- [DPE] Divide 2 on both sides: x² + 3x - 54 = 0
- Factor Quadratic: (x - 6)(x + 9) = 0
- Solve roots/solve <em>x</em>: x = -9, 6
Since we are dealing with positive values, we can disregard the negative root.
∴ x = 6
Answer:
Step-by-step explanation:
Start with h(t) = -16t^2 + initial height, which here is h(t) = -16t^2 + 1296. Set this = to zero, which corresponds to the object hitting the ground (h = 0):
0 = -16t^2 + 1296. Dividing all terms by -16, we get t^2 = 81, whose positive square root is 9. It takes 9 seconds for the object to hit the ground.