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olganol [36]
3 years ago
9

Solve each equation by graphing. Round to the nearest tenth. -2x^2+2=-3x

Mathematics
1 answer:
AlekseyPX3 years ago
5 0

Answer:

  x = -0.5 or x = 2

Step-by-step explanation:

Finding solutions graphically is often easier if the equation can be put in the form f(x) = 0. Here, we can do that by subtracting the right-side expression to give ...

  (-2x^2 +2) -(-3x) = 0

This could be put in standard form, but there is no need. A graphing calculator can deal with this directly.

The solutions are x = -0.5 and x = 2.

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2. Calculate the area of the rectangle below.<br>4 cm<br>IN<br>10 cm<br>Answer​
kozerog [31]

Answer:

40 cm squared

Step-by-step explanation:

Area = length * width

10*4cm = 40 cm squared

4 0
3 years ago
Orange M&amp;M’s: The M&amp;M’s web site says that 20% of milk chocolate M&amp;M’s are orange. Let’s assume this is true and set
SOVA2 [1]

Answer:

The correct option is (A).

Step-by-step explanation:

Let <em>X</em> = number of orange  milk chocolate M&M’s.

The proportion of orange milk chocolate M&M’s is, <em>p</em> = 0.20.

The number of candies in a small bag of milk chocolate M&M’s is, <em>n</em> = 55.

The event of an milk chocolate M&M being orange is independent of the other candies.

The random variable <em>X</em> follows a Binomial distribution with parameter <em>n</em> = 55 and <em>p</em> = 0.20.

The expected value of a Binomial random variable is:

E(X)=np

Compute the expected number of orange  milk chocolate M&M’s in a bag of 55 candies as follows:

E(X)=np

         =55\times 0.20\\=11

It is provided that in a randomly selected bag of milk chocolate M&M's there were 14 orange ones, i.e. the proportion of orange milk chocolate M&M's in a random bag was 25.5%.

This proportion is not surprising.

This is because the average number of orange milk chocolate M&M’s in a bag of 55 candies is expected to be 11. So, if a bag has 14 orange milk chocolate M&M’s it is not unusual at all.

All unusual events have a very low probability, i.e. less than 0.05.

Compute the probability of P (X ≥ 14) as follows:

P(X\geq 14)=\sum\limits^{55}_{x=14}{{55\choose x}0.20^{x}(1-0.20)^{55-x}}

                 =0.1968

The probability of having 14 or more orange candies in a bag of milk chocolate M&M’s is 0.1968.

This probability is quite larger than 0.05.

Thus, the correct option is (A).

4 0
3 years ago
How to remove Dec in casio calculator?<br> 0
vladimir1956 [14]

Answer:

htgjyk

Step-by-step explanation:

8 0
3 years ago
What is 2.53 rounded to the nearest whole number
ella [17]

Answer:

3.

Step-by-step explanation:

4 0
2 years ago
Whats this problem i need help
Eva8 [605]

Answer:

perimeter of triangle=sum of all sides

perimeter of triangle = 3/10ft + 3/10ft + 1/10ft

perimeter of triangle =7/10ft

6 0
2 years ago
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