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Radda [10]
3 years ago
7

What is 2.53 rounded to the nearest whole number

Mathematics
1 answer:
ella [17]3 years ago
4 0

Answer:

3.

Step-by-step explanation:

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Find the area of the trapezoid.
mestny [16]

Answer:

The area of the trapezoid is 90 cm².

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4 years ago
An insurance company sets up a statistical test with a null hypothesis that the average time for processing a claim is 7 days, a
belka [17]

Answer:

C. Type I error

Step-by-step explanation:

Hello!

The hypothesis tested was:

H₀: μ = 7

H₁: μ > 7

The decision was taken: Reject the null hypothesis.

Reminder:

There are four decisions you can take when you make a hypothesis test.

1. Reject the null hypothesis when the hypothesis is false (This is a correct decision)

2. Reject the null hypothesis when the hypothesis is true (This decision is also known as Type I error)

3. Fail to reject the null hypothesis when the hypothesis is true (This is a correct decision)

4. Fail to reject the null hypothesis when the hypothesis is false (This decision is also known as Type II error)

Since they concluded, that the average process time vas greater than 7 days, when it was 7 days, they rejected the null hypothesis when it was true. This is a Type I error and its associated probability is α.

I hope it helps!

6 0
4 years ago
I don’t understand.....someone help me.
maria [59]

Answer:x is 15

Step-by-step explanation:

7 0
4 years ago
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tiny-mole [99]

Answer:

I hope you feel better

Step-by-step explanation: don’t be sad

3 0
3 years ago
Read 2 more answers
The​ half-life of a certain tranquilizer in the bloodstream is 47 hours. How long will it take for the drug to decay to 93​% of
GaryK [48]

Answer:

It will take 4.84 hours for the drug to decay to 93​% of the original​ dosage.

Step-by-step explanation:

We are given that the half-life of a certain tranquilizer in the bloodstream is 47 hours.

The given exponential model is: A = A_0 e^{kt}

Now, we know that A becomes half after 47 hours which means that;

A = 0.5 A_0

Using this in the above equation we get;

A = A_0 e^{kt}

0.5 A_0 = A_0 e^{(k\times 47)}  where t = 47 hours

\frac{0.5 A_0}{A_0}  =  e^{(47k)}

0.5 = e^{47k}

Taking log on both sides we get;

ln(0.5) = ln(e^{47k})

ln(0.5) =47k

k = \frac{ln(0.5)}{47}

k = -0.015

Now, the time it will take for the drug to decay to 93​% of the original​ dosage is given by;

0.93 = e^{kt}  where t is the required time

0.93 = e^{(-0.015 \times t)}

Taking log on both sides we get;

ln(0.93) = ln(e^{-0.015t})

ln(0.93) =-0.015t

t = \frac{ln(0.93)}{-0.015}

t = 4.84 hours

Hence, it will take 4.84 hours for the drug to decay to 93​% of the original​ dosage.

8 0
4 years ago
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