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disa [49]
3 years ago
10

A square has a side of 3x - 4 what is the area of the Square in terms of x?

Mathematics
1 answer:
Doss [256]3 years ago
3 0

Answer:

9x2−24x+16

Hope this helps!

Step-by-step explanation:

The formula for a square is side times side since every side is of equal length. Because we are leaving the answer in terms of x you just multiply 3x-4 by 3x-4 and simplify and you get 9x2−24x+16

Please mark as brainliest :)

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Sec^2 (pi/2 - x) * [sin^2 (x) - sin^4 (x)]
Bad White [126]

Answer:

Explanation:

Identity:  sec2θ=1+tan2θ

sec2(π2−x)−1=1+tan2(π2−x)−1

=tan2(π2−x)

Identity: tan(π2−θ)=cotθ

=cot2x

4 0
2 years ago
Is 1/6 greater than 1/3
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No, 1/3 is greater than 1/6. 
1/3 converts to 2/6. 
2/6 > 1/6
4 0
3 years ago
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Line M is represented by the equation -2/3+8. Line W is perpendicular and passes through the point (4,3)
goblinko [34]

Answer:

y= -3/2x+9

Step-by-step explanation:

Well we have to know that to find a line perpendicular to a given line, you have to have opposite slopes. So that makes the equation begin as y=-3/2x because it's opposite of y=2/3x. Then we have to make sure it goes through the point (4,3). To do that, I tweaked the numbers in my graphing calculator and it worked with 9! So the equation is y= -3/2x+9

3 0
3 years ago
(12x + y + z = 26
mel-nik [20]

Option D. D has the matrix of constants [[12], [11], [4]].

Step-by-step explanation:

Step 1:

With the given equations, we can form matrices to represent them.

The coefficients of x, y, and z form a matrix of order 3 ×3, the variables x, y, and z form a matrix of order 1 ×3 and the constants form a matrix of order 1 ×3.

Step 2:

The linear system A is represented as

\left[\begin{array}{ccc}12&1&1\\1&-11&0\\1&-1&4\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}26\\17\\23\end{array}\right].

Step 3:

The linear system B is represented as

\left[\begin{array}{ccc}4&1&1\\1&-11&0\\1&-1&12\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}23\\17\\26\end{array}\right].

Step 4:

The linear system C is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}4\\11\\12\end{array}\right].

Step 5:

The linear system D is represented as

\left[\begin{array}{ccc}1&1&1\\1&-1&0\\1&-1&1\end{array}\right] \left[\begin{array}{ccc}x\\y\\z\end{array}\right] = \left[\begin{array}{ccc}12\\11\\4\end{array}\right].

Step 6:

Of the four options, the linear system D has the matrix of constants [[12], [11], [4]]. So the answer is option D. D.

4 0
3 years ago
Oranges sell for $5.00 per bag. If the bag weighs 2 pounds, how much is the price per pound?
svetoff [14.1K]

Answer:

$2.50

Step-by-step explanation:

Since there are 2 pounds in the bag, you simply divide $5.00 by 2 to get the price of a single pound.

4 0
3 years ago
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