The given equations are

(1)

(2)
When t=0, obtain

Obtain derivatives of (1) and find x'(0).
x' (t+1) + x - 4√x - 4t*[(1/2)*1/√x = 0
x' (t+1) + x - 4√x -27/√x = 0
When t=0, obtain
x'(0) + x(0) - 4√x(0) = 0
x'(0) + 9 - 4*3 = 0
x'(0) = 3
Here, x' means

.
Obtain the derivative of (2) and find y'(0).
2y' + 4*(3/2)*(√y)*(y') = 3t² + 1
When t=0, obtain
2y'(0) +6√y(0) * y'(0) = 1
2y'(0) = 1
y'(0) = 1/2.
Here, y' means

.
Because

, obtain

Answer:
The slope of the curve at t=0 is 1/6.
x = 14
Explanation:
height = x
base 1 = 98
base 2 = 2
Using altitude formula in geometric mean:
base 1/height = height/base 2
98/x = x/2

F(X) means plug in te number within the parenthesis for the given function. It's simply an equation expressed through different notation. In this case it asks you to plug in two, so you do:
-3(2)+4 = f(2)
That means that f(2)=-2.
Answer:
if area is given than use formula=πd²/4
if circumference=πd
Answer:
5 1 over 4
Step-by-step explanation: