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liq [111]
3 years ago
14

Pre-Test

Mathematics
1 answer:
fiasKO [112]3 years ago
5 0

Answer:

x5

Step-by-step explanation:

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The set of ordered pairs below represents a relation that is a function.
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I'm confused by the points:  

Why three points for each (A, B, C, and D)?: A: (0,6)(0,6)(0,6), etc.

Points A and B [(0,6) and (4,2)] are consistant with a straight line of the form y=-x+6.

Points C and D [(-6,8),(-8,10)]are on the line y=-x+2.  

A and B aren't related to C and D.

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Read 2 more answers
(0,65-3,21)por(-8,12)=?
PIT_PIT [208]

Answer:  =20,7872

Step-by-step explanation:

For this exercise it is important to remember the multiplication of signs. Notice that:

(+)(+)=+\\\\(-)(-)=+\\\\(-)(+)=-\\\\(+)(-)=-

In this case you have the following expression given in the exercise:

(0,65-3,21)(-8,12)

Then you can follow the steps shown below in order to solve it:

Step 1: You must solve the subtraction of the numbers 0,65 and 3,21. Then:

=(-2,56)(-8,12)

Step 2: Now you must find the product of the decimal numbers above. In order to do that you must multiply the numbers.

(As you can notice, both are negative, therefore you know that the product will be positive).

Then, you get that the result is the following:

 =20,7872

5 0
3 years ago
The sum of an arithmeit cprogression consisting of 20 positive integer terms with positive common difference is equal to 2020. (
Rufina [12.5K]

Answer:

a) possible progressions are 5

b) the smallest and largest possible values of the first term are 16 and 82

Step-by-step explanation:

<u>Sum of terms:</u>

  • Sₙ = n/2(a₁ + aₙ) = n/2(2a₁ + (n-1)d)
  • S₂₀ = 20/2(2a₁ + 19d) = 10(2a₁ + 19d)
  • 2020 = 10(2a₁ + 19d)
  • 202 = 2a₁ + 19d

<u>In order a₁ to be an integer, d must be even number, so d = 2k</u>

  • 202 = 2a₁ + 38k
  • 101 = a₁ + 19k

<u>Possible values of k= 1,2,3,4,5</u>

  • k = 1 ⇒ a₁ = 101 - 19 = 82
  • k = 2 ⇒ a₁ = 101 - 38 = 63
  • k = 3 ⇒ a₁ = 101 - 57 = 44
  • k = 4 ⇒ a₁ = 101 - 76 = 25
  • k = 5 ⇒ a₁ = 101 - 95 = 16

<u>As per above, </u>

  • a) possible progressions are 5
  • b) the smallest and largest possible values of the first term are 16 and 82
6 0
3 years ago
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