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3 years ago

84➗2 solve using area model

Mathematics

2 answers:

Ksju [112]3 years ago

5 0

The answer is 42
84
➗2
42

Phantasy [73]3 years ago

3 0

42 and just draw 8 tens and 4 ones and you have your answer:)

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Please help!!! thank you

fiasKO [112]

Answer:

Step-by-step explanation:

140 divided by 5 is 28

224 divided by 8 is 28

480 divided by 15 is 28

3 0

3 years ago

Read 2 more answers

How can you write -1/4x-9 on a graph

Dmitrij [34]

Answer:

Slope : -1/4

y-intercept : -9

x... 0 , 1

y... -9 , -37/4

Step-by-step explanation: Graph the line using the slope and y-intercept, or two points. GRAPH IS DOWN BELOW!

Hope this helps you out.

4 0

3 years ago

Solve the system of linear equations by elimination.<br> -3.x – 5y = -7<br> -4x + 5y = 14

julia-pushkina [17]

Answer:

(- 1, 2 )

Step-by-step explanation:

Given the 2 equations

- 3x - 5y = - 7 → (1)

- 4x + 5y = 14 → (2)

Add the 2 equations term by term to eliminate y , that is

- 7x + 0 = 7

- 7x = 7 ( divide both sides by - 7 )

x = - 1

Substitute x = - 1 into either of the 2 equations and solve for y

Substituting into (1)

- 3(- 1) - 5y = - 7

3 - 5y = - 7 ( subtract 3 from both sides )

- 5y = - 10 ( divide both sides by - 5 )

y = 2

solution is (- 1, 2 )

8 0

3 years ago

Read 2 more answers

Solve. Good luck! Please do not try to google this.

Elena L [17]

$\frac{x^{2} + x - 2}{6x^{2} - 3x} = \sqrt{2x} + \frac{3x^{2}}{2}$
$\frac{x^{2} + 2x - x - 2}{3x(x) - 3x(1)} = \frac{2\sqrt{2x}}{2} + \frac{3x^{2}}{2}$
$\frac{x(x) + x(2) - 1(x) - 1(2)}{3x(x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{x(x + 2) - 1(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$\frac{(x - 1)(x + 2)}{3x(2x - 1)} = \frac{2\sqrt{2x} + 3x^{2}}{2}$
$3x(2x - 1)(2\sqrt{2x} + 3x^{2}) = 2(x + 2)(x - 1)$
$3x(2x(2\sqrt{2x} + 3x^{2}) - 1(2\sqrt{2x} + 3x^{2}) = 2(x(x - 1) + 2(x - 1))$
$3x(2x(2\sqrt{2x}) + 2x(3x^{2}) - 1(2\sqrt{2x}) - 1(3x^{2})) = 2(x(x) - x(1) + 2(x) - 2(1)$
$3x(4x\sqrt{2x} + 6x^{3} - 2\sqrt{2x} - 3x^{2}) = 2(x^{2} - x + 2x - 2)$
$3x(4x\sqrt{2x} - 2\sqrt{2x} + 6x^{3} - 3x^{2}) = 2(x^{2} + x - 2)$
$3x(4x\sqrt{2x}) - 3x(2\sqrt{2x}) + 3x(6x^{3}) - 3x(3x^{2}) = 2(x^{2}) + 2(x) - 2(2)$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} + 18x^{4} - 9x^{3} = 2x^{2} + 2x - 4$
$12x^{2}\sqrt{2x} - 6x\sqrt{2x} = -18x^{4} + 9x^{3} + 2x^{2} + 2x - 4$
$6x\sqrt{2x}(2x) - 6x\sqrt{2x}(1) = -9x^{3}(2x) - 9x^{3}(-1) + 2(x^{2}) + 2(x) - 2(2)$
$6x\sqrt{2x}(2x - 1) = -9x^{3}(2x - 1) + 2(x^{2} + x - 2)$

5 0

3 years ago

Someone solve for me please WILL MARK THE BRAINLIEST FOR EXPLANATION !!!!!

Harrizon [31]

The answer to the question

7 0

3 years ago