Ok so assume that if you have
xy=0 then x and y=0
-1/4(x^2-4x+3)>0
multiply both sides by -4 to clear fraction (-4/-4=1)
flip sign
x^2-4x+3<0
factor
(x-3)(x-1)<0
we know that (+) times (-)=(-) and
(-) times (-)=(+) so we don't want them to be both negative, we want different sign
we cannnot have 3 since it would be (0)(2)<0 which is false
we cannot have 1 either since (-2)(0)<0 is also false
lets see if the solution is in betwen 3 and 1 or outside of 3 and 1
ltry 2
2^3-4(2)+3<0
8-8+3<0
3<0
false
therefor it is outside ie
x>3 and x<1
Answer:
27 years old
Step-by-step explanation:
Let Alvin's age be x and Elga's age is y:
y - x = 15
x + y = 27
2y = 42 (use elimination method)
y = 21
x = 6 (plug it back into either equation)
Therefore Alvin is 6 and Elga is 27
Plug in the to X value in
Answer:
C=0
Step-by-step explanation:
Answer:125.666
Step-by-step explanation:
