A) The probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
B) The probability the golfer got exactly two holes-in-one during a single game is 8.57%.
C) The probability the golfer got six holes-in-one during a single game is close to 0%.
<h2 /><h2><u>How to determine probabilities</u></h2>
Since a miniature golf player sinks a hole-in-one about 12% of the time on any given hole and is going to play 8 games at 18 holes each, to determine A) what is the probability the golfer got zero or one hole -in-one during a single game, B) what is the probability the golfer got exactly two holes-in-one during a single game, and C) what is the probability the golfer got six holes-in-one during a single game , the following calculations must be performed:
- 1 - 0.12 = 0.88
- 0.88 ^ 17 = 0.1138
- 0.88 ^ 18 = 0.1001
Therefore, the probability the golfer got zero or one hole-in-one during a single game is between 10.01% and 11.38%.
- 0.88 ^ 18 - 0.12 ^ 2 = X
- 0.0857 = X
Therefore, the probability the golfer got exactly two holes-in-one during a single game is 8.57%.
- 0.12 ^ 6 x 0.88 ^ 12 = X
- 0.0000000001 = X
Therefore, the probability the golfer got six holes-in-one during a single game is close to 0%.
Learn more about probabilities in brainly.com/question/25273534
Answer:
3(x+2)
Step-by-step explanation:
Answer:
0.70 hours= 42.0 minutes. All you have to do is multiply the 0.70 by 60.
Step-by-step explanation:
Answer:
The y intercept for this one is two.
In order to fully understand the problem, it is best to sketch it. Sketching the system, we will see that the system forms a triangle where the angle of elevation is 36 degrees. We are asked to find the hypotenuse. We can use a trigonometric function. It should be noted that one of the sides should also be given in order to calculate the hypotenuse. Trigonometric functions that can be used are:
sin(theta) = opposite / hypotenuse
cos(theta) = adjacent / hypotenuse
