Sorry if the handwriting bothered you.
You would turn this into a function f(x). So the constant rate (or slope) is 0.5, so you start off with f(x)=0.5x. But you know that it starts at 8000, which is your intercept. So your final result is
F(x)= 0.5x +8000
Well to find an area of a circle is (pi)R squared
This is the answer you are looking for babe which isn’t those two options
Answer:
df(t)/dt = 10 - 0.8f(t)
Step-by-step explanation:
The net rate of change, df(t)/dt = rate in - rate out
The rate in = rate litter forms on ground = 10 g/cm²/yr
Since f(t) is the amount of litter present at time, t, in g/cm² the rate out = rate of decomposition = the percentage rate × f(t) = 80% per year × f(t) = 0.8f(t) g/cm²/yr
Since df(t)/dt = rate in - rate out
df(t)/dt = 10 - 0.8f(t)
So the desired differential equation is
df(t)/dt = 10 - 0.8f(t)