Both of them you will quadratic formula to solve
Answer:
the greatest possible value for x is 6
Explanation:
Assume that the sides of the triangle are:
a = x
b = 3x
c = 20
We are given that c is the longest side.
For the triangle to be obtuse:
c^2 > a^2 + b^2
Substitute with the values of a, b and c and solve for x as follows:
c^2 > a^2 + b^2
(20)^2 > (x)^2 + (3x)^2
400 > x^2 + 9x^2
400 > 10 x^2
40 > x^2
Now, we will get the zeros of the function. This means that we will solve for x^2 = 40 as follows:
x^2 = 40
x = + or - √40
either x = 6.32
Or x = -6.32
Since we want x^2 < 40, therefore, the greatest possible value for x to satisfy this condition is 6
Hope this helps :)
answer:
15 square root of 6i
explanation:
square root of -54 can be re written as square root of -1 and square root of +54, the square root of -1 is basically i, and then the square root of 54 can be written as 9*6 and square root of 9 is 3
3 * 5 (which was outside the square root (see image) = 15 and square root of 6 is left along with the i
Left side from top to bottom blue, purple, blue