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2 years ago

9

Find the perimeter of the irregular hexagon with side lengths y, 2y + 11, -3y - 9, y^2, 5y - 1, and бу^2.

2 answers:

Lady bird [3.3K]2 years ago

6 0

Answer:

PERIMETER=Y+2Y+11+-3Y-9+Y^2+5Y-1+6Y^2

=7Y^2+4Y+1

Vlad1618 [11]2 years ago

5 0

Y＋2y＋11＋(－3y－9)＋y²＋(5y－1)＋6y²
＝y＋2y＋11－3y－9＋y²＋5y－1＋6y²
＝5y＋1＋7y²

Hope my answer helped u :)

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