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QveST [7]
3 years ago
9

Find the perimeter of the irregular hexagon with side lengths y, 2y + 11, -3y - 9, y^2, 5y - 1, and бу^2.​

Mathematics
2 answers:
Lady bird [3.3K]3 years ago
6 0

Answer:

PERIMETER=Y+2Y+11+-3Y-9+Y^2+5Y-1+6Y^2

=7Y^2+4Y+1

Vlad1618 [11]3 years ago
5 0
Y+2y+11+(-3y-9)+y²+(5y-1)+6y²
=y+2y+11-3y-9+y²+5y-1+6y²
=5y+1+7y²

Hope my answer helped u :)
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galben [10]
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Please help this is due today ;-;​
GrogVix [38]
The answer is the first one hope this helps!!
7 0
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Please help me with this.
OLga [1]

Swapping rows alters the sign of the determinant:

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = - \begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix}

Multiplying a single row by a scalar scales the determinant by the same amount:

\begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix} = -2 \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix}

Then

\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = -(-2) \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix} = 2\times(-6) = \boxed{-12}

8 0
2 years ago
If the x-intercept (–68, 0), and the y-intercept (0, –34), what is the equation?
stealth61 [152]

y = - \frac{1}{2} x - 34

the equation of a line in slope-intercept form is

y = mx + c ( m is the slope and c the y-intercept )

to calculate m use the gradient formula

m = ( y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (- 68, 0 ) and (x₂, y₂ ) = (0, - 34 )

m = \frac{-34-0}{0+68} = \frac{-34}{68} = - \frac{1}{2}

the y-intercept = (0, - 34 ) ⇒ c = - 34

y= - \frac{1}{2} x - 34


4 0
3 years ago
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saul85 [17]

Answer: D

Step-by-step explanation:

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7 0
2 years ago
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