Question

Find the perimeter of the irregular hexagon with side lengths y, 2y + 11, -3y - 9, y^2, 5y - 1, and бу^2.​

Answer 1

Answer:

PERIMETER=Y+2Y+11+-3Y-9+Y^2+5Y-1+6Y^2

=7Y^2+4Y+1

Answer 2

Y＋2y＋11＋(－3y－9)＋y²＋(5y－1)＋6y²
＝y＋2y＋11－3y－9＋y²＋5y－1＋6y²
＝5y＋1＋7y²

Hope my answer helped u :)