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brilliants [131]
4 years ago
12

Here is Morgan's solution to this problem. 6,404 + 2,857 = 9,261 Which expression could Morgan use to check her work? A. 9,261 +

2,857 B. 6,404 – 2,857 C. 9,261 + 6,404 D. 9,261 – 2,857
Mathematics
1 answer:
igor_vitrenko [27]4 years ago
3 0
<span>the answer is D. 9,261 – 2,857</span>
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How would you change 192 liters to kilograms?
Archy [21]
First you need to know the weight in Kilograms of one liter of the substance. Then you multiply that number by 192. For example, water weighs 1 kg per liter. This is an easy conversion, with 192 liters of water weighing 192 kilograms. The weight varies by substance, though, so you need to look up how much what you want weighs. 

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4 years ago
Claire says the expression 8x3 has tree terms 8,x and 3 is she correct?
Kazeer [188]

Answer:

nope not correct

Step-by-step explanation:

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6 0
2 years ago
Suppose that we wish to assess whether more than 60 percent of all U.S. households in a particular income class bought life insu
Yakvenalex [24]

Answer:

a) The probability is P=0.3982.

b) No. There is no enough evidence to say that the proportion of the population is not 0.6.

Step-by-step explanation:

a) In this question, we have a sample of the population, of size n=1000. To know what is the probability of observing a sample proportion that is at least 0.64 we have to know the parameters of the sampling distribution.

The parameters of the sampling distribution of the proportion will be:

\mu=\pi=0.6\\\\ \sigma=\sqrt{\frac{\pi(1-\pi)}{N} } =\sqrt{\frac{0.6(1-0.6)}{1000} }= 0.0155

With these parameters, we can calculate the z-value for p=0.64 as:

z=\frac{p-\pi}{\sigma}=\frac{0.64-0.6}{0.0155}=  0.258

Then, we can calculate the probability of having a sample with p≥0.64:

P(p\geq0.64)=P(z\geq0.258)=0.3982

b) To know if the proportion of the population is greater than 0.6 the rigth thing to do is perform a hypothesis test, in which we test the following hypothesis:

H_0: \pi\leq0.6\\\\H_1:\pi>0.6

If the null hypothesis is rejected, we can conclude that there is evidence that the proportion of the population is greater than 0.6.

First, we assume a significance level of 0.05.

Second, we calculate the z value:

z=\frac{p-\pi-0.5/N}{\sigma} =\frac{0.64-0.6-0.5/1000}{0.0155} =\frac{0.0395}{0.0155} =2.54

The P-value for this z is P=0.4. The P-value is greater than the significance level, what means that there is no evidence to reject the null hypothesis.

In other words, a sample mean of 0.64 is a quite probable value even if the proportion of the population is 0.6.

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