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Alja [10]
3 years ago
9

( 1/4) ꓥ -3 = A= -64 B= -1/64 C= 1/64 D= 64

Mathematics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

C-1/64

Step-by-step explanation:

(1/4)(1/4)(1/4)=1/64

<em>Mark the brainliest </em>

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A grasshopper jumps straight up from the ground with an initial vertical velocity of 8 feet per second. After how many seconds w
vlabodo [156]

Answer:

Problem 1 : After 0.25 s

Problem 2 : The squirrel doesn't reach the ground before the nut

Step-by-step explanation:

Problem 1

This is a standard physics problem

The equation that defines the movement of the grasshopper given the initial velocity, and the acceleration is the following

Distance =  Do + Vo*t + 0.5*a*t^2

Where

Do is the initial distance.

(Do = 0, because the grasshopper is on the ground and we choose the reference system there)

Vo is the initial velocity = 8 feet/sec

a is the acceleration that is exerted on the body (in this case a = g = -9.8 m/s^2 = - 32.174 feet per second per second.)

t is the time

We substitute in the equation, and solve for t (time)

Distance =  Do + Vo*t + 0.5*a*t^2

(1 foot)=  (0)+ (8 feet/s)*t + 0.5*(-32.174 feet/s^2)*t^2

Solving this equation, we get that

t = 0.25 s

Problem 2

This problem is similar to the previous one

We apply the same formula

D =  Do + Vo*t + 0.5*a*t^2

But in this case, we are going in the opposite direction, and we have an initial distance.

Do = 27 feet

Vo is the initial velocity of the nut = -6 feet/s

D = 0  (Ground)

We substitute in the equation, and solve for t (time)

(0) =  (27) + (-6 feet/s)*t + 0.5*(-32 feet/s^2)*t^2

t = 1.125 s  <  2s

The nut reaches ground in 1.125 s, so the squirrel doesn't reach the ground before the nut

4 0
3 years ago
HELP PLEASE IM REALLY STUCK
liberstina [14]
The 15th term will be 71. Why? Well, see below for an explanation!

By subtracting all of these numbers by the term that comes prior to them, we will find that all of them result in 5. Because of this, we know that each time the term increases, 5 is being added to the numbers. Additionally, I noticed that all of the numbers in this arithmetic sequence only end in a 1 or a 6. Because of this, we can apply the same principle when adding 5 each time:

First term: 1
Second term: 6
Third term: 11
Fourth term: 16
Fifth term: 21
Sixth term: 26
Seventh term: 31
Eighth term: 36
Ninth term: 41
Tenth term: 46
Eleventh term: 51
Twelfth term: 56
Thirteenth term: 61
Fourteenth term: 66
Fifteenth term: 71

By adding 5 each time and keeping in mind that the digits all end in only 1 or 6, we will find that the fifteenth term results in 71. Therefore, the 15th term is 71.

Your final answer: The 15th term of this arithmetic sequence comes down to be 71. If you need extra help, let me know and I will gladly assist you.
4 0
2 years ago
Lift pencil (10,7) graph
777dan777 [17]
Ya, what is the question?
6 0
3 years ago
What is the answer to 56-4
Scilla [17]

Answer:

The answer is 52.

Step-by-step explanation:

Subtract 56 by 4. You'll get 52.

5 0
3 years ago
Read 2 more answers
X^4 − 3x^2 − 90 x= -3
Ahat [919]

Answer:

-36

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

Step-by-step explanation:

<u>Step 1: Define</u>

x⁴ - 3x² - 90

x = -3

<u>Step 2: Evaluate</u>

  1. Substitute in <em>x</em>:                                                                                                  (-3)⁴ - 3(-3)² - 90
  2. Exponents:                                                                                                        81 - 3(9) - 90
  3. Multiply:                                                                                                             81 - 27 - 90
  4. Subtract:                                                                                                            54 - 90
  5. Subtract:                                                                                                            -36
8 0
3 years ago
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