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Alja [10]
3 years ago
9

( 1/4) ꓥ -3 = A= -64 B= -1/64 C= 1/64 D= 64

Mathematics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

C-1/64

Step-by-step explanation:

(1/4)(1/4)(1/4)=1/64

<em>Mark the brainliest </em>

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Solve the following problem.
SVEN [57.7K]

Answer:

What class is this for

Step-by-step explanation:

Bc I might know this

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3 years ago
Let X have the uniform distribution U(0, 2) and let the conditional distribution of Y , given that X = x, be U(0, x). Find the j
Elina [12.6K]

Answer:

f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x

E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \

Step-by-step explanation:

We have two random variables X and Y. X \sim Unif(0,2) and given that X=x, Y has uniform distribution (0,x)

From the definition of the uniform distribution we have the densities for each random variable given by:

f_X (x) =\frac{1}{2} , 0\leq x\leq 2

f_{Y|X} (y|x) = \frac{1}{x}, 0\leq y \leq x

And on this case we can find the joint density with the following formula:

f(x,y) = f_{Y|X}(y|x) f_X (x)

And multiplying the densities we got this:

f(x,y) = \frac{1}{x} \frac{1}{2}= \frac{1}{2x} , 0\leq x \leq 2 , 0\leq y \leq x

Now with the joint density we can find the expected value E(Y|x) with the following formula:

E(Y|x) = \int y f_{Y|X}(y|x)dx

And replacing we got:

E(Y|x) = \int_{x=y}^2 y \frac{1}{x} dx= y ln x \Big|_{x=y}^2 =y ln 2 -y ln y = y(1-lny) \

5 0
4 years ago
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baherus [9]
Answer: Your answer is correct.

Explanation:
Use the marker gradations to identify the projected geometric shapes from the top, front and right side view as shown in the figure below.

All the gradation markings agree with your choice.

.

3 0
3 years ago
Read 2 more answers
6)528<br> What is the answer????
Cloud [144]

Answer:

3168

Step-by-step explanation:

you mean (6)528

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4 0
3 years ago
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How many 1/4s fit in 1/2
WINSTONCH [101]

Answer:

2

Step-by-step explanation:

1/4+1/4=1/2

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4 years ago
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