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Alja [10]
3 years ago
9

( 1/4) ꓥ -3 = A= -64 B= -1/64 C= 1/64 D= 64

Mathematics
1 answer:
Anna11 [10]3 years ago
5 0

Answer:

C-1/64

Step-by-step explanation:

(1/4)(1/4)(1/4)=1/64

<em>Mark the brainliest </em>

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The rate of change of atmospheric pressure P with respect to altitude h is proportional to P, provided that the temperature is c
jonny [76]

Answer:

P = 101.5 e^{-0.00015h}

Step-by-step explanation:

dP/dh = kP

dP/P = k dh

ln P = kh + C

Now, using the points given,

ln 101.5 = C, so C = 4.62

ln 87.3 = k*1000 + 4.62

k = -0.00015

So, we have

ln P = -0.00015 h + ln 101.5

P = 101.5 e^(-0.00015h)

3 0
3 years ago
What is the x and What is the perimeter?
Anettt [7]

Answer:

7??? IDK this one is really messing with me

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Find the value of x in the<br> isosceles triangle shown below.<br> Help plzzzz
zysi [14]

Answer:

x =2

Option D is correct !!!

Step-by-step explanation:

By Pythagoras theorem we can solve this

we know that:

{x}^{2}  +  {4}^{2}  =  \sqrt{20} {}^{2}

{x}^{2}  =  \sqrt{20} ^{2}   - 16

{x}^{2} = 20 - 16

x = 2

6 0
4 years ago
Assume one individual from the group is randomly selected. Find the probability of getting someone who tests negative​, given th
KonstantinChe [14]

Answer:

P(Negative | Yes) = 0.0486

Step-by-step explanation:

Given

\begin{array}{ccc}{} & {Yes} & {No} & {Positive} & {137} & {24} & {Negative} & {7} & {132} \ \end{array}

Required

P(Negative | Yes)

This is calculated as:

P(Negative | Yes) = \frac{n(Negative\ n\ Yes)}{n(Yes)}

So, we have:

P(Negative | Yes) = \frac{7}{137+7}

P(Negative | Yes) = \frac{7}{144}

P(Negative | Yes) = 0.0486

4 0
3 years ago
Six ninth-grade students and six 12th-grade students were asked: How many movies have you seen this month? Here are their respon
steposvetlana [31]

Answer:

Following are the solution to the given point:

Step-by-step explanation:

Grade of students:

Grade of student:

In point a:

Grade of 9^{th} students:

\to n= 6\\\\\to Mean = \frac{ \sum x_i}{n} \\\\

               = \frac{ 5+1+2+5+2+8}{6}\\\\ = \frac{24}{6}\\\\ = 4

\to Variance\\\\\sigma^2 = \frac{\sum(x_i -\bar{x})^2}{n-1}

    =\frac{1}{5}(10)\\\\=2

\to Standard \ deviation ( \sigma) :\\\\= \sqrt{\sigma^2}\\\\= \sqrt{2}\\\\= 1.141

Since the Grade of 9^{th} student's variance is higher than 12^{th}grade,  

In point b:

Please find the attached file.

The plot above shows that the student of the ninth grade is spread more widely, as the student from 0-8 to 12 is from 0-4.

5 0
3 years ago
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