Find the value of 121 + 3 root 125
2 answers:
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Answer:
A. x = 16 , y = 34
B x = 2000, y = 1000
Step-by-step explanation:
Solution:-
- We will first define our variables ( x and y ) as follows:
x: The number of "nickels" in the jar
y: The number of "dimes" in the jar.
- Nest we will write down the rates of nickel and dime in dollar equivalent as ( P_n and P_d, respectively ) as follows:
P_n = $0.05 ... ( 5 cents )
P_d = $0.10 ... ( 10 cents )
- We are told that the jar contains a total of "50" coins comprised of nickel and dimes. Since, we don't know the exact amount of nickel and dimes in the jar. We will express the statement mathematically using the previously defined variables as follows:
... Eq1
- Secondly, the total worth of the jar is given to be " $4.2 ". The respectively value of each coin was iterated above. We will compute the total worth of the jar by expressing in terms of x and y as follows:
... Eq 2
- We have two equations [ Eq1 and Eq2 ] comprising of two variables. We can solve them simultaneously for a unique solution ( x and y ).
- To solve by elimination. We will first multiply the [ Eq1 ] by "- 0.1 " throughout as follows:
- Now we will add the two equations and eliminate the variable " y " and solve for " x ":
- Now plug the value of " x " in either of the derived equations and solve for "y":
Answer: There are 16 nickels and 34 dimes in the jar of total worth $4.2.
- We will first define our variables ( x and y ) as follows:
x: The number of "sodas" sold
y: The number of "hot dogs" sold.
- Nest we will write down the rate charged for soda and hot-dogs equivalent as ( P_s and P_h, respectively ) as follows:
P_s = $2 / soda
P_h = $3 / hot-dog
- We are told that " 3000 " sodas and hot-dogs were sold at the concession stand . Since, we don't know the exact amount of sodas and hot-dogs sold. We will express the statement mathematically using the previously defined variables as follows:
... Eq1
- Secondly, the total amount expressed on the receipts after selling "x" many sodas and " y " many hot--dogs was " $7000 ". The respectively value of each commodity sold was iterated above. We will compute the total value of items sold by expressing in terms of x and y as follows:
... Eq 2
- We have two equations [ Eq1 and Eq2 ] comprising of two variables. We can solve them simultaneously for a unique solution ( x and y ).
- To solve by elimination. We will first multiply the [ Eq1 ] by "-2 " throughout as follows:
- Now we will add the two equations and eliminate the variable " x " and solve for " y ":
- Now plug the value of " y " in either of the derived equations and solve for "x":
Answer: The concession sold 2000 sodas and 1000 hot-dogs of total worth $7000.
A= B+C
As given, A+B+C = 50000 seats
A+(B+C) = 50000
2A = 50000
A= 25000 seats
Now section A sells seats at $30 each
So,
Now, B+C = 25000
B = 25000-C
B sells at $24 and C sells at $18
So, 24B+18C = 538800
Now as section A incurs an amount of $750000 from booking, so B and C will incur 1288800-750000 = 538800 where $1288800 is the total booking amount.
24B+18C = 538800
6C = 61200
C = 10200
Now, B = 25000-C
B = 25000 - 10200 = 14800
Hence, section A has 25000 seats
Section B has 14800 seats
Section C has 10200 seats