Answer:
a) P(t>3)=0.30
b) P(t>10|t>9)=0.67
Step-by-step explanation:
We have a repair time modeled as an exponentially random variable, with mean 1/0.4=2.5 hours.
The parameter λ of the exponential distribution is the inverse of the mean, so its λ=0.4 h^-1.
The probabity that a repair time exceeds k hours can be written as:
(a) the probability that a repair time exceeds 3 hours?
(b) the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours?
The exponential distribution has a memoryless property, in which the probabilities of future events are not dependant of past events.
In this case, the conditional probability that a repair takes at least 10 hours, given that it takes more than 9 hours is equal to the probability that a repair takes at least (10-9)=1 hour.
For determining the period of a function, you pick two recognizable tops of the graph and calculate the time difference between them. In this situation the period is 5-1=4, by picking the first two tops
Answer:
Step-by-step explanation:
3v + u + 66 = 360
<em>Subtract 66 from 366</em>
3v + u = 294
<em>check images</em>
<em>for more steps</em>
Answer:
cubic units
Step-by-step explanation:
vyjf I thvjivgg b j
Answer:
a is the _amplitude_(Length of the blades)_
The vertical shift, k, is the _Mill shaft height_
Step-by-step explanation:
In this problem the amplitude of the sinusoidal function is given by the length of the blades.
The mill is 40 feet above the ground, therefore the function must be displaced 40 units up on the y axis. So:
We know that the blades have an angular velocity w = 3 rotations per minute.
One rotation = 
1 minute = 60 sec.
So:
Finally:
a is the _amplitude_(Length of the blades)_
The vertical shift, k, is the _Mill shaft height_
