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miss Akunina [59]
3 years ago
5

Sixty five percent of the 8th grade class is selling magazines for the class fundraiser. If 112students are selling magazines, h

ow many students are in the 8th grade class
Mathematics
1 answer:
IgorLugansk [536]3 years ago
3 0
112÷65=1.7230769231×100=172. So there is about 173 students in 8th grade class
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Which statement correctly compares the spreads of the distributions?
Pavlova-9 [17]

Answer:

Step-by-step explanation:

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To find the range, first order the data from least to greatest. Then subtract the smallest value from the largest value in the set.

The data has already been ordered for you so you take the highest number and subtract the smallest number.  

Cityview Zoo  44-37=7

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3 years ago
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A simple random sample of 125 SAT scores has a mean of 1522. Assume that SAT scores have a population standard deviation of 335.
Fed [463]

Answer:

1463.3\:

Step-by-step explanation:

Since the population standard deviation \sigma, is known, we use the z confidence interval for the mean.

This is given by:

\bar X-z_{\frac{\alpha}{2} }(\frac{\sigma}{\sqrt{n} } )\:

For a 95% confidence interval we use z=1.96.

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1522-1.96(\frac{335}{\sqrt{125} } )\:

1463.3\:

<u>Interpretation:</u>

We can say with 95% confidence that the interval between 1463.3 and 1580.7 SAT scores contains the population mean based on the sample 125 SAT scores.

7 0
3 years ago
What’s the area?? There’s a picture
Montano1993 [528]

Answer:

A= 12 Ft^2

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6 0
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Is it possible to scan a screenshot?
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To be honest  i dont know  but u can try to find something like that to help u ?

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3 years ago
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Solve the following integral.<br><br> <img src="https://tex.z-dn.net/?f=%5Cint4x%5Ccos%282-3x%29dx" id="TexFormula1" title="\int
bagirrra123 [75]

Hi there!

\boxed{-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C}

To find the indefinite integral, we must integrate by parts.

Let "u" be the expression most easily differentiated, and "dv" the remaining expression. Take the derivative of "u" and the integral of "dv":

u = 4x

du = 4

dv = cos(2 - 3x)

v = 1/3sin(2 - 3x)

Write into the format:

∫udv = uv - ∫vdu

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4x · (-1/3sin(2 - 3x)) -∫ 4(1/3sin(2 - 3x))dx

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Integrate the integral:

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Combine:

-\frac{4x}{3}sin(2-3x) + \frac{4}{9}cos(2-3x) + C

7 0
3 years ago
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