3 years ago

Can I get some help please

Mathematics

1 answer:

LenaWriter [7]3 years ago

4 0

Dividing integers is the opposite of multiplying integers.

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Please Help Me I will give Brainliest!

S_A_V [24]

Answer:

X= -1

Y= 2

Step-by-step explanation:

-1 + 3(2) = 5

-1 - 2 = -3

7 0

3 years ago

Read 2 more answers

Find the measure of angle 2 if m∠2=4x−26 and m∠4=3x+4

kotegsom [21]

Part A: What is the mean of the data? Show your work. (4 points)

Part B: Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)

5 0

4 years ago

Using the Order of Operations, what is the solution to 2(4/2)2 - 15 + 6?

PIT_PIT [208]

2(4/2)^2 - 15 + 6
= 2(2)^2 - 15 + 6
= 2(4) - 15 + 6
= 8 - 15 + 6
= -1

3 0

3 years ago

Read 2 more answers

Given the function f(x)=2x^3-7x^2-5x+1 find f(-2)

Ksju [112]

Answer:

-33

Step-by-step explanation:

2(-2)^3 -7(-2)^2 -5(-2) +1

-16 -28 +11

= -33

5 0

3 years ago

Need help with a simple problem 2^x=3^x+1

KiRa [710]

For $x\ \textgreater \ 0$ , $2^x\ \textless \ 3^x$ , all the more $2^x\ \textless \ 3^x+1$ , therefore no solution.

For $x=0$ , we have $2^0=3^0+1 \Rightarrow 1=1+1 \Rightarrow 1=2$ . Obviously that' false.

For $x\ \textless \ 0$ both $2^x$ and $3^x$ , where $2^x\ \textgreater \ 3^x$ , belong to the range $(0,1)$ , then $3^x+1$ belong to the range $(1,2)$ .
Those ranges don't have a common part, therefore, again, no solution.

So, the equation $2^x=3^x+1$ doesn't have a solution.

4 0

3 years ago