Answer:
(E) 0.83
Step-by-step explanation:
We will solve it using conditional probability.
Let A be the event that a TV show is successful.
P(A) = 0.5
A' be event that the show is unsuccessful
P(A') =0.5
Let B be the event that the response was favorable
P(B) = 0.6
Let B' be the event that the response was unfavorable/
P(B') = 0.4
P(A∩B) = 0.5 and P(A∩B') = 0.3
We need to find new show will be successful if it receives a favorable response.
P(A/B) =
= 0.5/0.6
= 0.833
Answer:
Step-by-step explanation:
It often works well to write an exponential expression as ...
value = (initial value)×(growth factor)^(t/(growth period))
(a) Here, the growth factor for the bacteria is given as 230/100 = 2.3 in a period of 1 hour. The initial number is 100, so we can write the pupulation function as ...
P(t) = 100·2.3^t
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(b) P(2) = 100·2.3^2 = 529 . . . number after 2 hours
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(c) P'(t) = ln(2.3)P(t) ≈ 83.2909·2.3^t
P'(2) = 83.2909·2.3^2 ≈ 441 . . . bacteria per hour
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(d) We want to find t such that ...
P(t) = 10000
100·2.3^t = 10000 . . . substitute for P(t)
2.3^t = 100 . . . . . . . . divide by 100
t·log(2.3) = log(100)
t = 2/log(2.3) ≈ 5.5 . . . hours until the population reaches 10,000
