Let the total toys be x.
The first has (1/10)x = x/10
The third child has one more toys than the first = x/10 + 1
The fourth has double of the third: = 2* (x/10 + 1) = 2x/10 + 2
Since we know that the second child has 12 more toys than the first
Therefore the Second minus First = 12.
First let us find the second.
1st + 2nd + 3rd + 4th = x
x/10 + 2nd + (x/10 + 1) + (2x/10 + 2) = x
2nd + x/10 + x/10 + 1 + 2x/10 + 2 = x
2nd + x/10 + x/10 + 2x/10 + 1 + 2 = x
2nd + 4x/10 + 3 = x
2nd = x - 4x/10 - 3
2nd = 6x/10 - 3
But recall
2nd - 1st = 12
6x/10 - 3 - x/10 = 12
6x/10 - x/10 = 12 + 3
5x/10 = 15
5x = 15 * 10
x = 15*10 /5
x = 30
So there were 30 toys in all.
Answer:
V = 300x + -70x2 + 4x3
Step-by-step explanation:
Simplifying
V = (20 + -2x)(15 + -2x)(x)
Reorder the terms for easier multiplication:
V = x(20 + -2x)(15 + -2x)
Multiply (20 + -2x) * (15 + -2x)
V = x(20(15 + -2x) + -2x * (15 + -2x))
V = x((15 * 20 + -2x * 20) + -2x * (15 + -2x))
V = x((300 + -40x) + -2x * (15 + -2x))
V = x(300 + -40x + (15 * -2x + -2x * -2x))
V = x(300 + -40x + (-30x + 4x2))
Combine like terms: -40x + -30x = -70x
V = x(300 + -70x + 4x2)
V = (300 * x + -70x * x + 4x2 * x)
V = (300x + -70x2 + 4x3)
Solving
V = 300x + -70x2 + 4x3
Solving for variable 'V'.
Move all terms containing V to the left, all other terms to the right.
Simplifying
V = 300x + -70x2 + 4x3
Answer:
it is -21
Step-by-step explanation:
make it braintliest please
1st let's calculate r the common ratio:
r = (-20)/4 = (100/-20) = -5
Value of nth term = a₁.rⁿ⁻¹, where a₁= 1st term and n, the rank
Value of nth term = 4r⁽⁷⁻¹⁾ = 4.(-5)⁶
Value of nth term = 62,500
Take out the -13 and add it to 43
