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kirza4 [7]
3 years ago
11

I cannot figure this problem out... can you help? Picture

Mathematics
2 answers:
Mkey [24]3 years ago
4 0
2880 would be the answer.

ArbitrLikvidat [17]3 years ago
3 0
2880 cubic inches is the answer.
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I know number 13 is right, how do I do 11 and 12?
snow_tiger [21]
11. 43 ; 137
12. 12 ; 102
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3 years ago
Simplify x+2/x^2+2x-3 divide by x+2/x^2-x
ira [324]

\dfrac{\frac{x+2}{x^2+2x-3}}{\frac{x+2}{x^2-x}}

If x\neq-2, then we can immediately cancel the factors of x+2:

\dfrac{\frac1{x^2+2x-3}}{\frac1{x^2-x}}=\dfrac{x^2-x}{x^2+2x-3}

Factorize the numerator and denominator:

x^2-x=x(x-1)

x^2+2x-3=(x+3)(x-1)

Next, if x\neq1, then

\dfrac{x^2-x}{x^2+2x-3}=\dfrac{x(x-1)}{(x+3)(x-1)}=\dfrac x{x+3}

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3 years ago
A fund earns a nominal rate of interest of 6\% compounded every two years. Calculate the amount that must be contributed now to
Nesterboy [21]

Answer:

$712.

Step-by-step explanation:

We have been given that a fund earns a nominal rate of interest of 6% compounded every two years. We are asked to find the amount that must be contributed now to have 1000 at the end of six years.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount,

P = Principal amount,

r = Annual interest rate in decimal form,  

n = Number of times interest is compounded per year,

t = Time in years.

6\%=\frac{6}{100}=0.06

Since interest is compounded each two years, so number of compounding per year would be 1/2 or 0.5.

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1000=P(1+0.12)^{3}

1000=P(1.12)^{3}

1000=P*1.404928

\frac{1000}{1.404928}=\frac{P*1.404928}{1.404928}

P=711.7802478

P\approx 712

Therefore, an amount of $712 must be contributed now to have 1000 at the end of six years.

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3 years ago
What is a polygonomial
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Answer:

See below

Step-by-step explanation:

Polynomials are sums of terms in the form of k⋅xⁿ, where k is any number and n is a positive integer. For example, 3x²+2x-5 is a polynomial.

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2 years ago
( 2 7/8 + 3 3/8 ) + 1 1/8 =​
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