3 years ago

Divide 56 in a ratio of 5.3

1 answer:

8 0

In order to find what one part is in a ratio, you have to add the ratio up ( 5+ 3) and divide it by the number you're looking for (56). In this case, you get 56/8, which gives you 7. Therefore, each part is worth 7. You then have to multiply both sides of the ratio (5 and 3) by 7. 5x7= 35. 3x7= 21. Therefore, 56 divided into the ratio of 5:3 is 35:21

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n200080 [17]

For this case we first write the equation of which we will use:
I (db) = 10log (l / l)
We substitute the value of l.
We have then:
l = 10 ^ 8lo
Substituting in the given equation:
I (db) = 10log ((10 ^ 8lo) / lo)
Rewriting:
I (db) = 10 * log (10 ^ 8)
I (db) = 80
Answer:
I (db) = 80
option 4

4 0

3 years ago

The function f(x) = (10)–x is reflected across the x-axis to create the function g(x). Which ordered pair is on g(x)? (–2, 75) (

IRINA_888 [86]

Neither point is on either function.
f(x) reflected over the x-axis is
y=-10 + x

7 0

3 years ago

I need help answering this question. Any ideas on what it could be?

Lesechka [4]

Is this for a test/exam?

4 0

3 years ago