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4 years ago

Can someone explain how to do this

Mathematics

1 answer:

n200080 [17]4 years ago

8 0

You need to divide the miles by the hours to et the Average speed.
M divided by h = s
Because to get the mph (miles per hour) you multiply the average speed to the hours.
S•h=mph

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What is the answer? The 8x-1x confused me. 10+ 8x -1x

dedylja [7]

Answer:

7x + 10

Step-by-step explanation:

10 + 8x - 1x

Add or subtract like terms.

10 + (8 - 1)x

10 + (7)x

Rearrange.

7x + 10

7 0

3 years ago

Read 2 more answers

Wat is 1/2 ÷ 1/3 please show work and simplify

s344n2d4d5 [400]

Make the denominators the same as the LCD 1/3 times 3 subtracted by 1/3 times 2
So it would be 3/6 subtracted by 2/6
The answer is 1/6

4 0

4 years ago

Is the relation a function? explain

Llana [10]

All functions are relations, but not all relations are functions. A function is a relation that for each input, there is only one output.

EXPLANATION;

Functions are relations that have only one output for any unique input. To tell whether a graphed relation defines a function, you can use the vertical line test.

8 0

3 years ago

Read 2 more answers

What is the solution of 3x+9<15

Zolol [24]

Answer:

Third one

Step-by-step explanation:

Two things to solve 3x+9 <= 15

3x <= 6

x <= 2

and - (3x+ 9) <= 15

- 3x - 9 <= 15

- 3x <= 24

3x >= -24

x > = - 8

s o -8 <= x <= 2

3 0

2 years ago

A 5-card hand is dealt from a perfectly shuffled deck. Define the events: A: the hand is a four of a kind (all four cards of one

TiliK225 [7]

In a hand of 5 cards, you want 4 of them to be of the same rank, and the fifth can be any of the remaining 48 cards. So if the rank of the 4-of-a-kind is fixed, there are $\binom44\binom{48}1=48$ possible hands. To account for any choice of rank, we choose 1 of the 13 possible ranks and multiply this count by $\binom{13}1=13$ . So there are 624 possible hands containing a 4-of-a-kind. Hence A occurs with probability

$\dfrac{\binom{13}1\binom44\binom{48}1}{\binom{52}5}=\dfrac{624}{2,598,960}\approx0.00024$

There are 4 aces in the deck. If exactly 1 occurs in the hand, the remaining 4 cards can be any of the remaining 48 non-ace cards, contributing $\binom41\binom{48}4=778,320$ possible hands. Exactly 2 aces are drawn in $\binom42\binom{48}3=103,776$ hands. And so on. This gives a total of

$\displaystyle\sum_{a=1}^4\binom4a\binom{48}{5-a}=886,656$

possible hands containing at least 1 ace, and hence B occurs with probability

$\dfrac{\sum\limits_{a=1}^4\binom4a\binom{48}{5-a}}{\binom{52}5}=\dfrac{18,472}{54,145}\approx0.3412$

The product of these probability is approximately 0.000082.

A and B are independent if the probability of both events occurring simultaneously is the same as the above probability, i.e. $P(A\cap B)=P(A)P(B)$ . This happens if

the hand has 4 aces and 1 non-ace, or
the hand has a non-ace 4-of-a-kind and 1 ace

The above "sub-events" are mutually exclusive and share no overlap. There are 48 possible non-aces to choose from, so the first sub-event consists of 48 possible hands. There are 12 non-ace 4-of-a-kinds and 4 choices of ace for the fifth card, so the second sub-event has a total of 12*4 = 48 possible hands. So $A\cap B$ consists of 96 possible hands, which occurs with probability

$\dfrac{96}{\binom{52}5}\approx0.0000369$

and so the events A and B are NOT independent.

4 0

3 years ago