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Nataly [62]
3 years ago
15

How do you work out the value of x?

Mathematics
2 answers:
denis23 [38]3 years ago
6 0

Answer: 45

Step-by-step explanation:

The total degrees in a circle is 360.

The perpendicular angle that you see is 90 degrees, added to angles of x and 3x, you get the total degrees.

so 90 + x + 3x = 90 + 4x = total

90 + 4x = 360

4x = 180

x = 45 degrees

densk [106]3 years ago
5 0

Answer:

360=90 degrees+x+3x

360-90=270 degrees

270÷4x

67.5 degrees

The answer is x=67.5 degrees

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Please help me with this!!
Burka [1]

Answer: yes

Step-by-step explanation:

Lets look at side AC and BC.

BC = 10

AC = 15

10/15 = 2/3

Now side CE and CD.

CD = 8

CE = 12

8/12 = 2/3

SO YES!

3 0
3 years ago
4. Solve for x in each diagram.<br> a.<br> X°<br> 108°<br> 156°
sveta [45]

Answer:

<h2>x = 48°</h2>

Step-by-step explanation:

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3 years ago
Which table represents a nonlinear function?
Simora [160]

Answer: c

Step-by-step explanation:

5 0
3 years ago
In a class of students, the following data table summarizes how many students have a cat or a dog. What is the probability that
leonid [27]

Given:

Number of students who has a cat and a dog = 5

Number of students who has a cat but do not have a dog = 11

Number of students who has a dog but do not have a cat = 3

Number of students who neither have a cat nor a dog = 2

To find:

The probability that a student has a cat given that they do not have a dog.

Solution:

Let the following events:

A = Student has a cat

B = Do not have a dog

Total number of outcomes is:

5+3+11+2=21

The probability that a student has a cat but do not have a dog is:

P(A\cap B)=\dfrac{11}{21}

The probability that a student do not have a dog is:

P(B)=\dfrac{11+2}{21}

P(B)=\dfrac{13}{21}

The conditional probability is:

P\left(\dfrac{A}{B}\right)=\dfrac{P(A\cap B)}{P(B)}

P\left(\dfrac{A}{B}\right)=\dfrac{\dfrac{11}{21}}{\dfrac{13}{21}}

P\left(\dfrac{A}{B}\right)=\dfrac{11}{13}

Therefore, the probability that a student has a cat given that they do not have a dog is \dfrac{11}{13}.

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3 years ago
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I think the answer to the question is,
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