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Valentin [98]
3 years ago
8

PLEASE HELP!! WILL MARK BRAINIEST !!

Mathematics
1 answer:
SOVA2 [1]3 years ago
3 0

Answer:

(f+g)(2) = 10

Step-by-step explanation:

f(x)=2x^2+3x

g(x)=x-2

(f+g)(x) will be sum of f(x) and g(x)

(f+g)(x)  = 2x^2+3x + x - 2 = 2x^2+4x - 2

we have to find  (f+g)(2), for that we will put x = 2

(f+g)(x)  = 2x^2+4x - 2

(f+g)(2)  = 2*2^2+2*2 - 2\\(f+g)(2)  = 2*4+4 - 2\\(f+g)(2)  = 8+4 - 2 = 10

Thus,  (f+g)(2) is 10.

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Which is the correct form of the quadratic formula?
d1i1m1o1n [39]

Answer:

The form ax2 + bx + c = 0 is called standard form of a quadratic equation. Before solving a quadratic equation using the Quadratic Formula, it's vital that you be sure the equation is in this form.

Step-by-step explanation:

5 0
4 years ago
12. In the given figure, RS is parallel to PQ, If RS = 3 cm, PQ = 6 cm and ar(∆TRS) = 15cm³, then ar (∆TPQ) = ? (a) 70 cm² (b) 5
Gnesinka [82]

\large\underline{\sf{Solution-}}

Given that,

In <u>triangle TPQ, </u>

  • RS || PQ,

  • RS = 3 cm,

  • PQ = 6 cm,

  • ar(∆ TRS) = 15 sq. cm

As it is given that, <u>RS || PQ</u>

So, it means

⇛∠TRS = ∠TPQ [ Corresponding angles ]

⇛ ∠TSR = ∠TPQ [ Corresponding angles ]

\rm\implies \: \triangle TPQ \:  \sim \: \triangle TRS \:  \:  \:  \:  \:  \:  \{AA \}

<u>Now, We know </u>

Area Ratio Theorem,

This theorem states that :- The ratio of the area of two similar triangles is equal to the ratio of the squares of corresponding sides.

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{ar( \triangle \: TRS)}  = \dfrac{ {PQ}^{2} }{ {RS}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{ {6}^{2} }{ {3}^{2} }

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = \dfrac{36 }{9}

\rm\implies \:\dfrac{ar( \triangle \: TPQ)}{15}  = 4

\rm\implies \:ar( \triangle \: TPQ)  = 60 \:  {cm}^{2}

3 0
2 years ago
[10] In the following given system, determine a matrix A and vector b so that the system can be represented as a matrix equation
irina1246 [14]

Answer:

y=-\frac{158}{579}

Step-by-step explanation:

To find the matrix A, took all the numeric coefficient of the variables, the first column is for x, the second column for y, the third column for z and the last column for w:

A=\left[\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right]

And the vector B is formed with the solution of each equation of the system:b=\left[\begin{array}{c}3\\-3\\6\\1\end{array}\right]

To apply the Cramer's rule, take the matrix A and replace the column assigned to the variable that you need to solve with the vector b, in this case, that would be the second column. This new matrix is going to be called A_{2}.

A_{2}=\left[\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right]

The value of y using Cramer's rule is:

y=\frac{det(A_{2}) }{det(A)}

Find the value of the determinant of each matrix, and divide:

y==\frac{\left|\begin{array}{cccc}1&3&2&2\\-7&-3&5&-8\\4&6&1&1\\3&1&-1&1\end{array}\right|}{\left|\begin{array}{cccc}1&1&2&2\\-7&-3&5&-8\\4&1&1&1\\3&7&-1&1\end{array}\right|} =\frac{158}{-579}

y=-\frac{158}{579}

7 0
3 years ago
Find the area of each figure. Round to the nearest hundredth where necessary. Only 1 and 5 please!
Alex787 [66]

Answer:

See below

Step-by-step explanation:

To begin, it is volume, not area

1. 8 x 12 x 17 = 1632 in ^3

5. 9 x 9 x 13.5 = 1093.5 in^3

If you want to find SURFACE AREA:

1. 2(8 x 12) + 2(8 x 17) + 2(17 x 12) = 872 in^2

5. 2(9 x 9) + 4(9 x 17) = 774 in^2

6 0
3 years ago
In 6n + 8, n is best described as ___. A a coefficient B a variable C an expression D a term
gayaneshka [121]
Variable, because its a letter<span />
6 0
3 years ago
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