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loris [4]
3 years ago
7

Every day, Paula performs physical activity on her treadmill. For an hour, she runs 15,000 meters. Knowing that she spends an ho

ur a day on the treadmill, how many kilometers does she run in a week?
Mathematics
1 answer:
natali 33 [55]3 years ago
3 0

Answer: 105 kilometers

Step-by-step explanation:

1 kilometer=1,000 meters

15,000 (meters a day) x 7 (days a week) = 105,000 meters.

Convert the meters to kilometers:

105,000/1,000 = 105 kilometers

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I need help ASAP!!!!!!
Fynjy0 [20]

Answer:

from what I see the...function 2

5 0
3 years ago
What is the perimeter of a parallelogram with base 32 cm, side length 34 cm, and height 19 cm?
Serjik [45]

Answer:

p=132cm^2

Step-by-step explanation:

Given the following question:

Formula for perimeter:

2(s+b)

We are given a base and a length for this parallelogram. So, to find the perimeter we simply have to substitute the values into the formula and solve.

2(s+b)
2(34+32)
34+32=66
2(66)
2(66)=2\times66=132
p=132cm^2

Hope this helps.

8 0
2 years ago
What is 2 2/3 x 3 1/3 x 2 1/3
madreJ [45]

Answer:

  20 20/27

Step-by-step explanation:

  (2 2/3)(3 1/3)(2 1/3) = (8/3)(10/3)(7/3) = 560/27 = 20 20/27

_____

<em>Additional comment</em>

The first two numbers can be written as a difference and a sum:

  = (3 -1/3)(3 +1/3)(2 1/3)

  = (3·3 -1/3·3 +3·1/3 -1/3·1/3)(2 1/3)

  = (9 -1/9)(2 +1/3) = 9·2 +9·1/3 -1/9·2 -1/9·1/3 = 18 +3 -6/27 -1/27

  = 20 20/27

7 0
2 years ago
Three assembly lines are used to produce a certain component for an airliner. To examine the production rate, a random
Katyanochek1 [597]

Answer:

a) Null hypothesis: \mu_A =\mu_B =\mu C

Alternative hypothesis: \mu_i \neq \mu_j, i,j=A,B,C

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2 =20.5  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 =12.333  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 =8.16667  

And we have this property  

SST=SS_{between}+SS_{within}  

The degrees of freedom for the numerator on this case is given by df_{num}=df_{within}=k-1=3-1=2 where k =3 represent the number of groups.

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-K=3*6-3=15.

And the total degrees of freedom would be df=N-1=3*6 -1 =15

The mean squares between groups are given by:

MS_{between}= \frac{SS_{between}}{k-1}= \frac{12.333}{2}=6.166

And the mean squares within are:

MS_{within}= \frac{SS_{within}}{N-k}= \frac{8.1667}{15}=0.544

And the F statistic is given by:

F = \frac{MS_{betw}}{MS_{with}}= \frac{6.166}{0.544}= 11.326

And the p value is given by:

p_v= P(F_{2,15} >11.326) = 0.00105

So then since the p value is lower then the significance level we have enough evidence to reject the null hypothesis and we conclude that we have at least on mean different between the 3 groups.

b) (\bar X_B -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_B}{n_B} +\frac{s^2_C}{n_C}}

The degrees of freedom are given by:

df = n_B +n_C -2= 6+6-2=10

The confidence level is 99% so then \alpha=1-0.99=0.01 and \alpha/2 =0.005 and the critical value would be: t_{\alpha/2}=3.169

The confidence interval would be given by:

(43.333 -41.5) - 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}= 0.321

(43.333 -41.5) + 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}=3.345

Step-by-step explanation:

Previous concepts

Analysis of variance (ANOVA) "is used to analyze the differences among group means in a sample".  

The sum of squares "is the sum of the square of variation, where variation is defined as the spread between each individual value and the grand mean"

Part a  

Null hypothesis: \mu_A =\mu_B =\mu C

Alternative hypothesis: \mu_i \neq \mu_j, i,j=A,B,C

If we assume that we have 3 groups and on each group from j=1,\dots,6 we have 6 individuals on each group we can define the following formulas of variation:  

SS_{total}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x)^2 =20.5  

SS_{between}=SS_{model}=\sum_{j=1}^p n_j (\bar x_{j}-\bar x)^2 =12.333  

SS_{within}=SS_{error}=\sum_{j=1}^p \sum_{i=1}^{n_j} (x_{ij}-\bar x_j)^2 =8.16667  

And we have this property  

SST=SS_{between}+SS_{within}  

The degrees of freedom for the numerator on this case is given by df_{num}=df_{within}=k-1=3-1=2 where k =3 represent the number of groups.

The degrees of freedom for the denominator on this case is given by df_{den}=df_{between}=N-K=3*6-3=15.

And the total degrees of freedom would be df=N-1=3*6 -1 =15

The mean squares between groups are given by:

MS_{between}= \frac{SS_{between}}{k-1}= \frac{12.333}{2}=6.166

And the mean squares within are:

MS_{within}= \frac{SS_{within}}{N-k}= \frac{8.1667}{15}=0.544

And the F statistic is given by:

F = \frac{MS_{betw}}{MS_{with}}= \frac{6.166}{0.544}= 11.326

And the p value is given by:

p_v= P(F_{2,15} >11.326) = 0.00105

So then since the p value is lower then the significance level we have enough evidence to reject the null hypothesis and we conclude that we have at least on mean different between the 3 groups.

Part b

For this case the confidence interval for the difference woud be given by:

(\bar X_B -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_B}{n_B} +\frac{s^2_C}{n_C}}

The degrees of freedom are given by:

df = n_B +n_C -2= 6+6-2=10

The confidence level is 99% so then \alpha=1-0.99=0.01 and \alpha/2 =0.005 and the critical value would be: t_{\alpha/2}=3.169

The confidence interval would be given by:

(43.333 -41.5) - 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}= 0.321

(43.333 -41.5) + 3.169 \sqrt{\frac{0.6667}{6} +\frac{0.7}{6}}=3.345

7 0
3 years ago
What is the prime factorization of 28 and 50?<br> Explain if possible.
dangina [55]

Answer:

prime factorization of 28

28 = 2 × 2 × 7

prime factorization of 50

50 = 2 × 5 × 5

Step-by-step explanation:

GCF, multiply all the prime factors common to both numbers:

Therefore, GCF = 2

3 0
2 years ago
Read 2 more answers
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