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weeeeeb [17]
3 years ago
9

How do I find the surface area of a regular hexagonal pyramid if there is no middle height given

Mathematics
1 answer:
k0ka [10]3 years ago
7 0
Bahehhehdjdhdhndndndnndjff
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My neighbors daughter was playing with a book and tore out the pages7,8,100,101,222 and 223. How many sheets did she tear out?
monitta

Answer:

6

Step-by-step explanation:

3 0
3 years ago
A line passes through the point (2, -9) and has a slope of -9. Write an equation in point-slope form for this line.
Natali [406]

Answer:

y+9 = - 9x +18

Step-by-step explanation:

Line is passing through the point (2,\: - 9) =(x_1,\:y_1) and has slope (m) = - 9

General equation of line in point slope form is given as:

y-y_1 = m(x-x_1)

Therefore

y-(-9) = - 9(x-2)

y+9 = - 9x +18

This is the required equation of line in point slope form.

4 0
3 years ago
GIVING BRAINLEST Which table represents the statement “A car is traveling at a rate of 60 miles per hour”? A 2-column table with
-BARSIC- [3]

Answer:

im not shere but i think its D on ege

Step-by-step explanation:

4 0
3 years ago
The radius of a circular plate is 12 centimeters. What is the area, in square centimeters, of this plate? Write your Anwer using
lesya [120]

Answer:

The area of circular plate is <u>144π square centimeters</u>.

Step-by-step explanation :

<h3><u>Solution</u> :</h3>

Here, we have given that the radius of circular plate is 12 centimeters.

So, finding the area of circular plate by substituting the values in the formula :

\longrightarrow{\pmb{\sf{Area_{(Circle)} = \pi{r}^{2}}}}

\longrightarrow{\sf{Area_{(Circle)} = \pi{(12)}^{2}}}

\longrightarrow{\sf{Area_{(Circle)} = \pi{(12 \times 12)}}}

\longrightarrow{\sf{Area_{(Circle)} = \pi{(144)}}}

\longrightarrow{\sf{Area_{(Circle)} = \pi \times 144}}

\longrightarrow{\sf{Area_{(Circle)} = 144\pi}}

\star{\underline{\boxed{\frak{\purple{Area_{(Circle)} = 144\pi\:  {cm}^{2}}}}}}

Hence, the area of circular plate is 144π square centimeters.

\rule{300}{2.5}

5 0
2 years ago
A barrier in the shape of a rectangle is used to retain oil spills. On a blueprint, a similar barrier is 9 inches long and 2 inc
drek231 [11]

Width of the actual barrier = 1.2 miles

Width of the barrier in the blueprint = 2 inches

2 inch dimension of blueprint = 1.2 miles of original

So, 1 inch dimension of blueprint = 1.2/2 = 0.6 miles.

Since the length of the barrier in the blueprint = 9 inches,

length of the actual barrier = 9(0.6) = 5.4 miles.

5 0
3 years ago
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