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dlinn [17]
3 years ago
9

A company makes two sizes of cylindrical shaped boxes. The ratio of the heights is 5:7.

Mathematics
1 answer:
Dmitrij [34]3 years ago
8 0

Answer:

The volume ratio is also 5 : 7

Step-by-step explanation:

The volume of a cylinder is given by the following formula:

volume = pi*r²*h

Since we have two cylinders and their height varies at a ratio of 5:7 we can say that the smaller one has a height of "h" while the bigger has height of "(7/5)*h". Thefore their volume is:

volume smaller = pi*r²*h

volume bigger = pi*r²*(7/5)*h

volume bigger = (7/5)*pi*r²*h

The ratio of their volume is given by the division of the smaller volume by the bigger one:

volume ratio = volume smaller / volume bigger

volume ratio = (pi*r²*h) / [(7/5)*pi*r²*h] = 1/(7/5)

volume ratio = 5/7

The volume ratio is also 5 : 7.

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About how much cardboard is needed to make the inner tube for a roll of paper if the tube has a radius of 2.25 cm and is 24 cm l
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2 years ago
40 points and brainliest to the best correct answer, questions in photo.
vodomira [7]

Answer:

2. w = -3

4. c = -2

6. r = 7

8. n = 4

Step-by-step explanation:

It's hard to read the photo, but I'll try.

2.

2^{w + 4} \times 2^{4w + 6} = 2^{2w + 1}

On the left side, you have a product of 2 powers with the same base.

Give the same base and add the exponents, as in the rule

a^m \times a^n = a^{m + n}

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2^{w + 4 + 4w + 6} = 2^{2w + 1}

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Here, 2 to the power 5w + 10 equals 2 to the power 2w + 1. Since both bases are 2 and are equal, then the exponents must be equal.

5w + 10 = 2w + 1

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w = -3

4.

\dfrac{1}{5} = 5^{2c + 3}

We need to write the left side as a power of 5. Then we equate the exponents like we did in problem 2.

Recall the rule:

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Apply this rule to the left side in reverse.

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6.

216 = 6^{2r - 11}

This is the same idea as problem 4. Write the left side as a power of 6.

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r = 7

r = 7

8.

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This problem is similar to problem 2.

4^{n + 2n - 9} = 4^3

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3n - 9 = 3

3n = 12

n = 4

4 0
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