4 years ago

Part A: What is the solution to the pair of equations represented by p(x) and f(x)? (3 points)

1 answer:

3 0

Solution for part A is where the red line and the red line meet, (2,-1)
solution for part B: any point on the blue red line is a solution. (2, -1), (0, 3), (3, -3), (-2, 7)
solution for part C is where the green curve and the blue line meet, (0,3)

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EastWind [94]

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3 years ago

Use the quadratic formula to find the solutions to the quadratic equation below x^2-6x-5=0

Sonja [21]

Answer:

$\large\boxed{x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}}$

Step-by-step explanation:

$x^2-6x-5=0\qquad\text{add 5 to both sides}\\\\x^2-6x=5\\\\x^2-2(x)(3)=5\qquad\text{add}\ 3^2\ \text{to both sides}\\\\x^2-2(x)(3)+3^2=5+3^2\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2\\\\(x-3)^2=5+9\\\\(x-3)^2=14\to x-3=\pm\sqrt{14}\qquad\text{add 3 to both sides}\\\\x=3-\sqrt{14}\ \vee\ x=3+\sqrt{14}$