Short answer yes its true
Equals 1 over 7 because 63/9 is 7. The answer is 1/7
So firstly, you want to multiply both sides by (x-2)(x+2) since it is the LCM, or lowest common multiplier. Your equation will look like this: ![\frac{3}{x+2} (x-2)(x+2)-\frac{4}{x-2} (x-2)(x+2)=5(x-2)(x+2)](https://tex.z-dn.net/?f=%20%5Cfrac%7B3%7D%7Bx%2B2%7D%20%28x-2%29%28x%2B2%29-%5Cfrac%7B4%7D%7Bx-2%7D%20%28x-2%29%28x%2B2%29%3D5%28x-2%29%28x%2B2%29%20)
Next, you can cancel out the denominators on 3/x+2 and 4/x-2 on the left side: ![3(x-2)-4(x+2)=5(x-2)(x+2)](https://tex.z-dn.net/?f=%203%28x-2%29-4%28x%2B2%29%3D5%28x-2%29%28x%2B2%29%20)
Next, foil: ![3x-6-4x-8=5x^2-20](https://tex.z-dn.net/?f=%203x-6-4x-8%3D5x%5E2-20%20)
Next, combine like terms: ![-x-14=5x^2-20](https://tex.z-dn.net/?f=%20-x-14%3D5x%5E2-20%20)
Next, add x + 14 on both sides: ![0=5x^2+x-6](https://tex.z-dn.net/?f=%200%3D5x%5E2%2Bx-6%20)
Next, replace x with -5x + 6x: ![0=5x^2-5x+6x-6](https://tex.z-dn.net/?f=%200%3D5x%5E2-5x%2B6x-6%20)
Next, factor 5x^2-5x and 6x-6 separately. Make sure that both factors have the same quantity within the parentheses: ![0=5x(x-1)+6(x-1)](https://tex.z-dn.net/?f=%200%3D5x%28x-1%29%2B6%28x-1%29%20)
With this, we can rewrite it as
From here, we solve for x in (5x+6) and (x-1) separately and setting them to zero.
![5x+6=0\\ 5x=-6\\x=-\frac{6}{5} =-1.2](https://tex.z-dn.net/?f=%205x%2B6%3D0%5C%5C%205x%3D-6%5C%5Cx%3D-%5Cfrac%7B6%7D%7B5%7D%20%3D-1.2%20%20)
![x-1=0\\ x=1](https://tex.z-dn.net/?f=%20x-1%3D0%5C%5C%20x%3D1%20)
In short, x = -1.2, 1.
Answer:
A. median is 12 but b has larger mean
Answer:
y = 26
Step-by-step explanation:
Given y varies directly as x and inversely as the square of z then the equation relating them is
y =
← k is the constant of variation
To find k use the condition y = 52, x = 16, z = 2
k =
=
= 13
y =
← equation of variation
When x = 18 and z = 3, then
y =
= 26