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3 years ago

The bowl of a circular birdbath has an inside diameter of 18 inches, as shown in the drawing belon.

Mathematics

1 answer:

Step2247 [10]3 years ago

4 0

Answer:

254 square inches

Step-by-step explanation:

A=pi*r^2

A=pi*(d/2)^2

A=3.14*(18/2)^2

A=3.14*(9)^2

A=3.14*81

A=254.34 in^2

So, rounded no the nearest whole, the answer is 254 in^2

Which is option 2 or B

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2x -9 < 7<br> Please answer

Marysya12 [62]

Answer:

18(<) 7= False

Step-by-step explanation:

1)-9×2=18

2)18(<) 7

3) The equation is Fasle.

6 0

3 years ago

Consider two functions f and g on [1, 8] such that integral^8_1 f(x) dx = 9, integral^8_1 g(x) dx = 5, integral^8_5 f(x) dx = 4,

Gelneren [198K]

I'll abbreviate the definite integral with the notation,

$I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx$

We're given

$I(f,1,8)=9$
$I(g,1,8)=5$
$I(f,5,8)=4$
$I(g,1,5)=3$

Recall that the definite integral is additive on the interval $[a,b]$ , meaning for some $c\in[a,b]$ we have

$I(f,a,b)=I(f,a,c)+I(f,c,b)$

The definite integral is also linear in the sense that

$I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)$

for some constant scalars $k,\ell$ .

Also, if $a\ge b$ , then

$I(f,a,b)=-I(f,b,a)$

a. $I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}$

b. $I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}$

c. $I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}$

d. $I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}$

e. $I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}$

f. $I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}$

4 0

3 years ago

What is the next three numbers out of the pattern 60 54 48 and 42

aleksandrvk [35]

The next three are 36, 30, and 24

4 0

3 years ago

Ty and Gajge are both football players who averaged 4 yards per run in yesterday’s

Anettt [7]

Answer:

The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs is the answer.

Step-by-step explanation:

given that Ty and Gajge are football players.

Carries is 15 for both and average is the same 4 for both.

But on scrutiny we find that maximum and minimum and 6 and 2 for Ty.

Hence range for Ty = 6-2 =4 (2 runs on eithre side of mean)

But for Gajge, highest is 19 and lowest is 2.

i.e. range = 19-2 =17 very much higher than that of Ty

The lengths of Gajge’s runs have greater variability because there is a greater difference between his longest and shortest runs.

5 0

3 years ago

Prove the quotient rule. hint: you can do this directly, but it may be easier to find the derivative of 1/x and then use the cha

Bess [88]

The quotient rule is
d(u/v) = (u dv - v du) / u2

d(u/v) can written as
d( u (1/v) )

Using the product rule and chain rule
d( u (1/v)) = u d(1/v) + (1/v) du
= u (-1/v2) dv + (!/v) du
= (u dv - v du) / u2

5 0

3 years ago