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inysia [295]
3 years ago
5

What is the maximum value of P = 24x + 30y, given the constraints on x and y listed below? x+y (less than or equal to) 5 x-y (gr

eater than or equal to) -1 x (greater than or equal to) 0 y (greater than or equal to) 0 120 132 138 150
Mathematics
1 answer:
valentina_108 [34]3 years ago
6 0

Answer:

Step-by-step explanation:

We have to first find the vertices of the feasible region before we can determine the max value of P(x, y). We will graph all 4 of those inequalities in a coordinate plane and when we do that we find that the region of feasibility is bordered by the vertices (0, 0), (0, 1), (2, 3), and (5, 0). Filling each x and y value into our function will give us the max value of that function.

Obviously, when we sub in (0, 0). we get that P(x, y) = 0.

When we sub in (0, 1) we get 24(0) + 30(1) = 30.

When we sub in (2, 3) we get 24(2) + 30(3) = 138.

When we sub in (5, 0) we get 24(5) + 30(0) = 120.

Obviously, the vertex of (2, 3) maximized our function for a value of 138.

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I hoped this helped or something

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3 years ago
4x-y=10 and y=2x-2 answers
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4x - y = 10, y = 2x - 2

4x - (2x -2) = 10

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2x = 8

x = 4

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