3 years ago

3k^2+29/4k-250=0 find k.

Mathematics

2 answers:

dem82 [27]3 years ago

4 0

Answer:

k=8

Step-by-step explanation:

zheka24 [161]3 years ago

3 0

First multiple both sides by 4 = 12k^2+29k-1000, rewrite it 12k^2+125k-96k-1000=0, factor k out from the expression k x (12k+125)-96k-1000=0, then factor out 8 k x (12k+125)-8(12k+125)=0, factor out 12k+125 to (12k+125)x(k-8)=0, now when the product of factors equals 0, at least one factor is 0 - 12k+125=0 k-8=0, solve the equation for k k=-125/12

k=8

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3k^2+29/4k-250=0 find k.​

3k^2+29/4k-250=0 find k.