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3 years ago

10PTS PLEASE HELP!!!!!!!

Mathematics

1 answer:

Nostrana [21]3 years ago

6 0

The equation of a circle:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - a coordinates of the center

r - a radius

A diameter d = 2r

We have

$x^2+(y-2)^2=100\to r^2=100\to r=\sqrt{100}\to r=10$

Answer: d = 2 · 10 = 20

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Darin has a rectangular vegetable garden. It is 5 yards long and 8 feet wide.

Lelu [443]

Answer:

about 15.328 yrds

Step-by-step explanation:

two sides are 5 yrds, so 5+5= 10yrds. two sides are 8 ft, 8+8=16 ft. there are .3333 yrds in 1 foot so 16*.3333 = about 5.328yrds

10+5.328 = 15.328

7 0

3 years ago

Mathew deposits 400800.00 kina with the bank which offers 5½% interest per annum. calculate the interest earned after four years

Sati [7]

Solution

For this case we can use the following formula:

$A=P(1+\frac{r}{n})^{nt}$

Where:

P= 400800 = present value

A= future value

r= 0.055 interest rate

n= 4, number of times that the interest is compund in a year (quarterly)

t= 4 years

Replacing we got:

$A=400800(1+\frac{0.055}{4})^{4\cdot4}=498679.58$

then the interest would be:

$I=A-P=498679.58-400800=97879.58$

4 0

1 year ago

Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the

kodGreya [7K]

Answer:

p=0.7103 (4-game series)
p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters n=4, p=0.6:

$P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\ i=4,5,6,7$

#We find probabilities for the different values of i:

$P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659$

Hence, probability of the stronger team winning overall is:

$=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103$

#Define Y as the random variable for winning 2/3 games.:

$P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480$

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0

3 years ago

PLEASE HELP. NO LINKS OR U WILL BE REPORTED MAKE SURE U ARE RIGHT I WILL GIVE BRAINLY THING

dmitriy555 [2]

Answer:

The answer is B to your question

6 0

3 years ago

A golf tournament has five rounds. The players are given scores for each round based on how many strokes they are above or below

Sedaia [141]

Answer:

(A) ∫₁⁵[Xₙ + k] where n ranges from 1 to 5

(B) 73.6

Step-by-step explanation:

The question is clear enough. Kudos!

So there are many players but we're focusing on Ricky.

Ricky has already recorded his score for each of the 5 rounds in the tournament.

The number of strokes in Ricky's record are to be added to or subtracted from a given number 72

ROUND 1: [72 - 5] strokes = 67

ROUND 2: [72 + 6] strokes = 78

ROUND 3: [72 - 2] strokes = 70

ROUND 4: [72 + 4] strokes = 76

ROUND 5: [72 + 5] strokes = 77

(A) Write an expression to represent Ricky's total number of strokes for the five rounds.

Do not panic at this first exercise. You are to write an expression which when evaluated, will give the total number of strokes for all five rounds!

You are already given an abstract number '72' to work with in this question.

It is a fixed quantity which influences the value of strokes for each round.

We will represent this by an algebra, if we have to create the above required expression.

The expression will then be:

∫₁⁵[Xₙ + k] where n ranges from 1 to 5

You already know that the sigma sign '∫' represents summation and that's summation from the subscript '1' to the superscript '5'.

X₁ would be -5, X₂ would be +6, X₃ would be -2, X₄ would be +4, X₅ would be +5

K is the constant 72

(B) What was Ricky's average number of strokes per round?

Out of the 5 rounds, the average number of strokes per round would be

[67 + 78 + 70 + 76 +77] ÷ 5

= 368/5 = 73.6

6 0

3 years ago