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3 years ago

5

Correct and best explained answer gets brainliest. :)

2 answers:

kodGreya [7K]3 years ago

6 0

The question asks that y is equal to 0. So the equation should be 0 = x² - 64. Now you can use the addition property of equality by adding 64 to both sides. This gives you x² = 64. Now, to find x, you need to find the root of 64, which is √64. However this can be simplified to a whole number 8. However, this isn't it. The answer actually can be 8 or -8, because -8² = 64 as well, because a negative multiplied by a negative is a positive. So your answer would be B. 8 or -8. Hope this helps. Feel free to ask questions about my explanation or any other questions you have.

son4ous [18]3 years ago

3 0

Y = x^2 - 64
x^2 - 64 = 0
x^2 = 64
x^2 = 8^2
x = 8 and x = -8
answer is B. x = 8 and x = -8

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Use the reciprocal property to solve for x:

Natali5045456 [20]

Answer:

The answer is 1800.

Step-by-step explanation:

3/540 = 10/x

3x = 540 × 10

x = 5400/3

x = 1800

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3 years ago

What equation represents the line that passes through the points (-3 7 and (3 3?

dexar [7]

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3 years ago

Bee + ant= 10, ant - bee = 8, ant × bee= ?

Alona [7]

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7 0

3 years ago

If f(x) = 4x - 12, what is f(2)?<br> O A. -4<br> O'B. 4<br> O c. -20<br> D. 8<br> Helpppp plzzz

photoshop1234 [79]

Answer:

-4

Step-by-step explanation:

f(x) = 4x - 12

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f(2) = 4*2 - 12

= 8-12

= -4

8 0

2 years ago

Andre45 [30]

Answer:

$a_n=-3(3)^{n-1}$ ; {-3,-9, -27,- 81, -243, ...}

$a_n=-3(-3)^{n-1}$ ; {-3, 9,-27, 81, -243, ...}

$a_n=3(\frac{1}{2})^{n-1}$ ; {3, 1.5, 0.75, 0.375, 0.1875, ...}

$a_n=243(\frac{1}{3})^{n-1}$ ; {243, 81, 27, 9, 3, ...}

Step-by-step explanation:

The first explicit equation is

$a_n=-3(3)^{n-1}$

At n=1,

$a_1=-3(3)^{1-1}=-3$

At n=2,

$a_2=-3(3)^{2-1}=-9$

At n=3,

$a_3=-3(3)^{3-1}=-27$

Therefore, the geometric sequence is {-3,-9, -27,- 81, -243, ...}.

The second explicit equation is

$a_n=-3(-3)^{n-1}$

At n=1,

$a_1=-3(-3)^{1-1}=-3$

At n=2,

$a_2=-3(-3)^{2-1}=9$

At n=3,

$a_3=-3(-3)^{3-1}=-27$

Therefore, the geometric sequence is {-3, 9,-27, 81, -243, ...}.

The third explicit equation is

$a_n=3(\frac{1}{2})^{n-1}$

At n=1,

$a_1=3(\frac{1}{2})^{1-1}=3$

At n=2,

$a_2=3(\frac{1}{2})^{2-1}=1.5$

At n=3,

$a_3=3(\frac{1}{2})^{3-1}=0.75$

Therefore, the geometric sequence is {3, 1.5, 0.75, 0.375, 0.1875, ...}.

The fourth explicit equation is

$a_n=243(\frac{1}{3})^{n-1}$

At n=1,

$a_1=243(\frac{1}{3})^{1-1}=243$

At n=2,

$a_2=243(\frac{1}{3})^{2-1}=81$

At n=3,

$a_3=243(\frac{1}{3})^{3-1}=27$

Therefore, the geometric sequence is {243, 81, 27, 9, 3, ...}.

6 0

3 years ago