Chebyshev came up with the
limits on how much or how many of the data must lie close to the mean. In specific
for any positive k, the proportion of the data that lies within k standard
deviations of the mean is at least: <span>
1 - 1/k²
<span>In this problem the
mean is 47 yrs therefore:
(47 – 17.3) = 29.7 = (76.7 - 47) </span></span>
The value of k is
calculated using the formula:<span>
29.7 / 11 = 2.7 = k</span>
So the % of gym members
aged between 19.4 and 76.6 is: <span>
1 - 1 / (2.6)² = 0.863 = 86.3 %</span>
<span>Therefore 86.3% of the
gym members are aged between 19.4 and 76.6</span>
Answer:
1/4
Step-by-step explanation:
Answer:
M(h) = 73.18025h
Step-by-step explanation:
The composite function is ...
M(B(L(h))) = M(B(28.75h)) = M(1.78(28.75h)) = M(51.175h)
= 1.43(51.175h) = 73.18025h
The composite function is ...
M(h) = M(B(L(h))) = 73.18025h
Answer:
The smaller number is 127
Step-by-step explanation:
Lets write the given problem in equation form
sum of consecutive numbers n and n + 1 = n + n + 1 = 2n + 1
now we find twice of the sum of consecutive numbers n and n + 1
2*(2n + 1) = 4n + 2
given that
twice the sum of consecutive numbers n and n + 1 is 510
thus,
4n + 2 = 510
=> 4n = 510 -2 = 508
=> n = 508/4 = 127
Thus, the numbers are n = 127
n+1 = 127 + 1 = 128
the smaller number is 127