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enyata [817]
4 years ago
5

Item 19 A cylindrical container of four rubber balls has a height of 20 centimeters and a diameter of 5 centimeters. Each ball i

n the container has a radius of 2.5 centimeters. Find the amount of space in the container that is not occupied by rubber balls. Round your answer to the nearest whole number.
Mathematics
1 answer:
Lady_Fox [76]4 years ago
7 0
First you need to find the volume of the cylinder. Then find the volume of all 4 rubber balls (spheres). Subtract the cylinder's volume by the spheres' volumes.

Volume of cylinder: πr²h
                                   π2.5²(20) = 392.7 cm³

Volume of sphere: 4/3πr³
                                 4/3π2.5³ = 65.45 cm³

392.7 - 65.45 = 327.25

The amount of space in the container unoccupied by the rubber balls is 327 cm³.
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Step-by-step explanation:

all models are correct other than the first model and the third model.

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What’s the quotient of 20 and 2
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the answer is 10 hoped this helped have a great day


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A pharmaceutical company receives large shipments of aspirin tablets. The acceptance sampling plan is to randomly select and tes
Pavel [41]

Answer:

0.818

Step-by-step explanation:

Since the shipment has a ton of aspirin tablets, we can assume that we pick 13 of them <em>with</em> <em>reposition, </em>because the probability shoudn't change dramatically from the probability of picking without reposition if we do so.

We call D the amount of defective tablets. If we assume that we pick the tablets with reposition, then we obtain that D is a random variable of Binomial distribution with parameters 13 and 0.6 (the probability of picking a defective tablet).

We want D to be at most one. To calculate the probability of that event we add up the probability of D being equal to 0 and the probability of D being equal to one. Since D is binomial, we have

  • P(D = 0) = (1-0.06)^{13} = 0.447
  • P(D = 1) = {13 \choose 1} * 0.06^1 * (1-0.06)^{12} = 13*0.06*0.94^{12} = 0.371

We conclude that

P(D \leq 1) = P(D = 0) + P(D = 1) = 0.447+0.371 = 0.818

Hence, the shipment will be accepted with probability 0.818

<em>I hope this helps you!</em>

6 0
3 years ago
Domain of f(x)=150x+2500
HACTEHA [7]
All real numbers would be the domain here
8 0
3 years ago
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A 400-meter Olympic-size track can be modeled with a rectangle and two semicircles.
pishuonlain [190]

The answer to both the subparts using the circumference of the circle is:

  • (A) If an athlete runs around the track then the athlete traveled (168.78+73π)m.
  • (B) The area of green space on the track is 0.64m².

<h3>What is a length of a rectangle?</h3>
  • The length of the rectangle is traditionally thought of as being the longer of these two dimensions, however, when the rectangle is depicted standing on the ground, the vertical side is typically referred to as the length.

What is a circumference of a circle?

  • The distance along a circle's perimeter is referred to as its circumference.
  • Circumference of the circle formula: C = 2πr.

Here,

(A) A circuit of a racetrack is equal to the sum of the two lengths of a rectangle and the circumference of the circle.

We get:

  • = 84.39 * 2 + 73π
  • = (168.78 + 73π)m

(B) Let the area of the green space of the track is x.

Then, calculate as follows:

  • 168.78 + xπ = 400
  • x = (400 - 168.78)/π
  • x = 73.64m

So, the inner circle of distance is 73.64 - 73 = 0.64m.

Therefore, the answer to both the subparts using the circumference of the circle is:

  • (A) If an athlete runs around the track then the athlete traveled (168.78+73π)m.
  • (B) The area of green space on the track is 0.64m².

To learn more about the circumference from the given link

brainly.com/question/18571680

#SPJ13

7 0
1 year ago
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