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Sliva [168]
3 years ago
8

Domain of f(x)=150x+2500

Mathematics
2 answers:
HACTEHA [7]3 years ago
8 0
All real numbers would be the domain here
Elena-2011 [213]3 years ago
4 0
The domain is all real numbers, since there is no given y value.
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Both the ranges and the interquartile ranges for the data sets are the same.
aleksley [76]

Answer:

to find range of interquartile sets of data

you see 5 vertical lines 1 is start point 2 is start of 2nd quartile 3 is start of 3rd quartile and also represents the median.  the 4th start of 4th quartile and 5th is very end point.

Therefore the interquartile is from start line 2 to start line 4

apply to each by if it says 10 and 34 then we show workjings 34-10 = 24 and that is the range once we deduct data from each other.

Therefore full range is start line 1 to end line 5

if this says 2 to 45 then full range is 45-2 = 43 and apply to each boxplot.

Step-by-step explanation:

6 0
2 years ago
Jenna has 8 pairs of jeans. Three of them are blue.Jenna bought two more pairs of jeans. If both of them are blue, what percenta
vovikov84 [41]

Answer:62.5%

Step-by-step explanation:You do 5/8 and then divide it and you will get a decimal and move the number 0.625 back to the tens which will get you 6.25%

7 0
3 years ago
What is the solution for -6(1-5v)=54 ?
snow_tiger [21]

Isolate the variable by dividing each side by the factors that don't contain the variable

v=2

4 0
3 years ago
Read 2 more answers
Suppose a parabola has vertex (6,5) and also passes through the point (7,7). Write the equation of the parabola in vertex form.
jek_recluse [69]

Answer:

Choice B: y = 2\, (x - 6)^{2} + 5.

Step-by-step explanation:

For a parabola with vertex (h,\, k), the vertex form equation of that parabola in would be:

\text{$y = a\, (x - h)^{2} + k$ for some constant $a$}.

In this question, the vertex is (6,\, 5), such that h = 6 and k = 5. There would exist a constant a such that the equation of this parabola would be:

y = a\, (x - 6)^{2} + 5.

The next step is to find the value of the constant a.

Given that this parabola includes the point (7,\, 7), x = 7 and y = 7 would need to satisfy the equation of this parabola, y = a\, (x - 6)^{2} + 5.

Substitute these two values into the equation for this parabola:

7 = (7 - 6)^{2}\, a + 5.

Solve this equation for a:

7 = a + 5.

a = 2.

Hence, the equation of this parabola would be:

y = 2\, (x - 6)^{2} + 5.

4 0
3 years ago
What is the approximate square root of 12 to the nearest integer
Licemer1 [7]

Answer:

3

Step-by-step explanation:

3² =  9, so  √9 = 3

4² = 16, so √16 = 4.

12 is closer to 9 than to 16, so √12 is closer to √9 than to √16.

√12 ≈ 3 (to the closest integer)

5 0
4 years ago
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