Answer:
The probability that the last card dealt is an ace is
.
Step-by-step explanation:
Given : A deck of ordinary cards is shuffled and 13 cards are dealt.
To find : What is the probability that the last card dealt is an ace?
Solution :
There are total 52 cards.
The total arrangement of cards is 52!.
There is 4 ace cards in total.
Arrangement for containing ace as the 13th card is
.
The probability that the last card dealt is an ace is
![P=\frac{4\times 51!}{52!}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B4%5Ctimes%2051%21%7D%7B52%21%7D)
![P=\frac{4\times 51!}{52\times 51!}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B4%5Ctimes%2051%21%7D%7B52%5Ctimes%2051%21%7D)
![P=\frac{4}{52}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B4%7D%7B52%7D)
![P=\frac{1}{13}](https://tex.z-dn.net/?f=P%3D%5Cfrac%7B1%7D%7B13%7D)
Therefore, the probability that the last card dealt is an ace is
.
2x^3+3x^2+9x+7 is the answer
Step-by-step explanation:
9) y= -2x - (5/2)
10) y = -5 + (5/2)
The answer is 3
hope this helps :)
Answer:
4 markers
Step-by-step explanation:
1/2 miles divided by 1/8 miles equals 4 markers.
1/2 ÷ 1/8
Apply the fraction rule:
1/2 × 8/1
Cross cancel common factor 2:
= 4/1
= 4
Hope this helps!